Question

Calculate the pH of a 0.10 M solution of NaOH. Express your answer numerically using two decimal places. ► View Available Hint(s) IVO AQ O ? pH = Submit Part C Calculate the pH of a 0.10 M solution of hydrazine, NH K! for hydrazine is 1.3 x 10-6 Express your answer numerically using two decimal places! View Available Hint(s) 70 AED + O2 ? pH =

Answer 1

Now, 0.10(M) Neon Solution meam, . [Not] =B. 0.101m) and (or] = 0.10(M) pOH = -log [on-] = -loy, 0.10 = 1 pH + pOH = 14 pH = 14- POH =14-1 -13 10 : Colentated pH=13

Nata + 120 - Noths + + OH 0.10 0 0 0 ...initially (0.10-x) -x x x ... -at equilibrium The concentration of water in neglected as huge amount of 4₂0 present. Let x mol of Ng Hq dinoeiste reacts to form & mole oh ko= x² Now, ka 1.3x10-6 & 1-3x10-6 = x2 - Ool-2 - x² = 0.13 x 106 - 1.3x10x x + 1.3x18 6x = 0.13x10-6 = 0 Solving this a - 1.3x100 I (1-3 + 8%) 2 _ 9.1. (- 0.13x156) -1.3 x 156 + 7.21x107 = 3.599x180 (teking & Sign) If we take – sign then xn negetire which is Valuelem. x= [OH-] = 3.599x10-9 pott -lo, Soh] 5- g636#0-1) = -104 (3-599x10 ") = 3.44 :. pH = 14-3.44 = 10.56