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![initial final ka= HN3 - HT + N3 . Ka=1.9x105 oisin : osete [ht] [N] = x² = 19 x105 Dulsar LHN3] a. re=1068 Xi03 [HT] = x. = 1](http://img.homeworklib.com/questions/21143010-d446-11eb-8481-57c60ac6d7a5.png?x-oss-process=image/resize,w_560)
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QUESTION 23 The Ka of hydrazoic acid (HN3) is 1.9 x 10-5 at 25.0 °C. What...
The Ka of hydrazoic acid (HN3) is 1.9 x 10-5 at 25°C. What is the pH...
The Ka of hydrazoic acid (HN3) is 1.9 x 10-5 at 25°C. What is the pH of a 0.35 M solution of HN3? 2.59 5.23 2.41 O 1.14
The pH of a 0.10 M solution of hydrazoic acid, HN3, is 2.86. Calculate the Ka...
The pH of a 0.10 M solution of hydrazoic acid, HN3, is 2.86. Calculate the Ka value for hydrazoic acid. A. 1.4 x 10-4 B. 1.9 x 10-5 C. 1.9 x 10-3 D. 1.4 x 10-5 E. 2.6 x 10-3
Part A Calculate the percent dissociation of 0.17 M hydrazoic acid (HN3, KA = 1.9 x...
Part A Calculate the percent dissociation of 0.17 M hydrazoic acid (HN3, KA = 1.9 x 10-5). Express your answer using two significant figures. IVO AXO ? % of dissociation = 96 Submit Request Answer Part B Recalculate the percent dissociation of 0.17 M HN3 in the presence of 0.17 M HCI. Express your answer using two significant figures. ΤΙ ΑΣΦ ? % of dissociation = 96 Submit Request Answer Part C Explain the change. Essay answers are limited to...
8) The Ka of hydrofluoric acid (HF) at 25.0 C is 6.8 x10-4. What is the...
8) The Ka of hydrofluoric acid (HF) at 25.0 C is 6.8 x10-4. What is the pH of a 0.15 M aqueous 8) solution of HF? A) 4.60 B) 0.82 C)3.64 D) 1.17 E) 2.00
3. (3 points) An aqueous solution is prepared by mixing hydrazoic acid (HN3) and NaNg and...
3. (3 points) An aqueous solution is prepared by mixing hydrazoic acid (HN3) and NaNg and then allowed to come to equilibrium. Upon addition of sulfuric acid (a) more N31- will be formed and the pH will not change (b) more N31- will be formed and the pH will decrease (c) more HN3 will be formed and the pH will decrease (d) more HN3 will be formed and the pH will not change (e) impossible to answer without knowing ka...
The pH of a solution of HN3 (Ka = 1.9 x10^-5) and NaN3 is 4.86. What...
The pH of a solution of HN3 (Ka = 1.9 x10^-5) and NaN3 is 4.86. What is the molarity of NaN3 if the molarity of HN3 is 0.016 M?
Ka= 1.9*10^-5 i Review | Constants | Periodic Table Calculate the percent ionization of hydrazoic acid...
Ka= 1.9*10^-5
i Review | Constants | Periodic Table Calculate the percent ionization of hydrazoic acid (HN3) in solutions of each of the following concentrations (Ka is given in Appendix D in the textbook). Part A 0.424 M. Express your answer using two significant figures. IVO A o 2 ? ΑΣΦ Submit Request Answer Part B 0.100 M Express your answer using two significant figures. od 0 0 ? ΑΣΦ Part C 4.18x10-2 M. Express your answer using two significant...
a) The active ingredient in Aspirin™ is acetylsalicylic acid, HC9H7O4 (Ka = 2.75 x 10–5). To...
a) The active ingredient in Aspirin™ is acetylsalicylic acid, HC9H7O4 (Ka = 2.75 x 10–5). To treat your headache after writing exams, you take two tablets dissolved in 250 mL of water. If each tablet contains 0.32 g acetylsalicylic acid, find the pH of the solution. Proper pH significant digit is required for full marks. b)Hydrazine, N2H4, is a base in aqueous solution. A 0.20 mol/L solution of hydrazine in water has pH = 10.77. What is Kbfor hydrazine? Express...
26. -10.1 points 0/4 Submissions Used A buffer solution contains 0.10 mol of hydrazoic acid (HN3)...
26. -10.1 points 0/4 Submissions Used A buffer solution contains 0.10 mol of hydrazoic acid (HN3) and 0.43 mol of sodium hydrazoate (NaN3) in 1.70 L. The Ka of hydrazoic acid (HN3) is ka = 1.92-05. (a) What is the pH of this buffer? pH = (b) What is the pH of the buffer after the addition of 0.05 mol of NaOH? (assume no volume change) pH = (c) What is the pH of the original buffer after the addition...
Calculate the percent ionization of hydrazoic acid (HN3) in solutions of each of the following concentrations...
Calculate the percent ionization of hydrazoic acid (HN3) in solutions of each of the following concentrations (Ka is given in Appendix D in the textbook). 1.9 * 10^-5 Part A: 0.372 M Express your answer using two significant figures. Part B: 0.112 M Express your answer using two significant figures. Part C: 4.31×10−2 M . Express your answer using two significant figures.
The Ka of hydrazoic acid (HN3) is 1.9 x 10-5 at 25°C. What is the pH of a 0.35 M solution of HN3? 2.59 5.23 2.41 O 1.14
Part A Calculate the percent dissociation of 0.17 M hydrazoic acid (HN3, KA = 1.9 x 10-5). Express your answer using two significant figures. IVO AXO ? % of dissociation = 96 Submit Request Answer Part B Recalculate the percent dissociation of 0.17 M HN3 in the presence of 0.17 M HCI. Express your answer using two significant figures. ΤΙ ΑΣΦ ? % of dissociation = 96 Submit Request Answer Part C Explain the change. Essay answers are limited to...
8) The Ka of hydrofluoric acid (HF) at 25.0 C is 6.8 x10-4. What is the pH of a 0.15 M aqueous 8) solution of HF? A) 4.60 B) 0.82 C)3.64 D) 1.17 E) 2.00
3. (3 points) An aqueous solution is prepared by mixing hydrazoic acid (HN3) and NaNg and then allowed to come to equilibrium. Upon addition of sulfuric acid (a) more N31- will be formed and the pH will not change (b) more N31- will be formed and the pH will decrease (c) more HN3 will be formed and the pH will decrease (d) more HN3 will be formed and the pH will not change (e) impossible to answer without knowing ka...
Ka= 1.9*10^-5
i Review | Constants | Periodic Table Calculate the percent ionization of hydrazoic acid (HN3) in solutions of each of the following concentrations (Ka is given in Appendix D in the textbook). Part A 0.424 M. Express your answer using two significant figures. IVO A o 2 ? ΑΣΦ Submit Request Answer Part B 0.100 M Express your answer using two significant figures. od 0 0 ? ΑΣΦ Part C 4.18x10-2 M. Express your answer using two significant...
26. -10.1 points 0/4 Submissions Used A buffer solution contains 0.10 mol of hydrazoic acid (HN3) and 0.43 mol of sodium hydrazoate (NaN3) in 1.70 L. The Ka of hydrazoic acid (HN3) is ka = 1.92-05. (a) What is the pH of this buffer? pH = (b) What is the pH of the buffer after the addition of 0.05 mol of NaOH? (assume no volume change) pH = (c) What is the pH of the original buffer after the addition...
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