590.7 mL of a 0.37 M solution of ammonia is mixed with 590.7 mL of a 0.37 M solution of HBr. What is the pH of the resulting solution of NH4Br? (Kb for NH3 equals 1.8 × 10-5)
590.7 mL of a 0.37 M solution of ammonia is mixed with 590.7 mL of a...
If 20.9 mL of 0.071 M hydrochloric acid (HCI) solution is added to 21 mL of 0.132 M ammonia (NH3) solution, what is the pH value of the mixed solution at 25°C? (Kb for NH3 = 1.8 x 10-5); Please keep your answer to two decimal place x.xx.
A 78.0 mL sample of 0.260 M NH3 is titrated with 149 mL of 0.094 M HBr. What is the pH of the resulting solution? (Kb = 1.8 * 10-5 )
A buffer solution is prepared by combining 750.0 ml of 1.00 M of ammonia and 250 ml of 1.00 M ammonium chloride. What is the pH of the buffer? ( Ka of NH4+=5.6*10^-10, Kb of NH3= 1.8*10^-5)
A buffer solution is prepared by combining 750.0 ml of 1.00 M of ammonia and 250 ml of 1.00 M ammonium chloride. What is the pH of the buffer? ( Ka of NH4+=5.6*10^-10, Kb of NH3= 1.8*10^-5)
Practice Exercise 16.29 599.2 ml of a 0.11 M solution of ammonia is mixed with 599.2 mL of a 0.11 M solution of HBr. What is the pH of the resulting solution of NH Br? (K for NH, equals 1.8 x 10) pH = the tolerance is +/-2% Click if you would like to show Work for this questioni Deen Short Work x Incorrect. Does your answer make sense given the Ka? The K, for HF is 6.8 x 10-4....
A chemistry graduate student is given 250.mL of a 0.60M ammonia NH3 solution. Ammonia is a weak base with =Kb×1.810−5. What mass of NH4Br should the student dissolve in the NH3 solution to turn it into a buffer with pH =9.35?
Ka * Kb = Kw = 1.0 X 10-14 A 25.0 ml sample of a 0.100 M solution of aqueo us ammonia is titrated with a 0.125 M solution of HCI. Calculate the pH of the solution after 0.00, 10.0, 20.0, 30.00, and 40.0 mL of acid have been added; Kb of NH3= 1.8 X 10-5 at 25 °C. Hint: First find the moles after each 10.00 ml of acid is added. Then find the concentration after equilibrium is reached.
calculate the pH when 50.0 mL of 0.4 M NH3 is mixed with 5.00 mL of 0.8 M HCl. ( The ka of ammonia is 1.77 x10^-5.) KaKb=Kw (Ka)(Kb)=1.00 x 10^-14
A 101.6 mL sample of 0.104 M HCl is mixed with 35.8 ml of 0.085 M NH3. What is the resulting pH? (The Ky for NH3 = 1.8 x 10-5).
a) What is the pH of a solution that consist of 0.20 M ammonia, NH3, and 0.20 M ammonium choride, NH4Cl? (Kb for ammonia is 1.8 x 10-5) b) 1.25 g of benzoic acid (C6H5CO2H) and 1.25 g of sodium benzoate (NaC6H5CO2) are dissolved in enough water to make 250 mL solution. Calculate the pH of the solution using the Handerson-Hasselbach equation (Ka for benzoic acid is 6.3 x 10-5). c) What is the pH after adding 82 mg of...