![38. Calculate the (Ca2+] required to start the precipitation of calcium fluoride, CaF2, from a solution containing 0.0025 MF-](http://img.homeworklib.com/questions/35c68f10-d46f-11eb-9ba7-7708eac438f8.png?x-oss-process=image/resize,w_560)
the correct answer is highlighted. how do i get the correct answer?
Homework Answers
CaF2 <----------> Ca+2 + 2F-
Ksp = [Ca+2][F-]2
Ksp = 3.9 x 10-11
[F-] = 0.0025 M
[Ca+2] = ?
3.9 x 10-11 = [Ca+2] [0.0025]2
3.9 x 10-11 = [Ca+2] [0.00000625]
[Ca+2] = 6.2 x 10-6 M
answer = option d = 6.2 x 10-6 M
Add Answer to:
the correct answer is highlighted. how do i get the
correct answer?
38. Calculate the (Ca2+]...
the correct answer is highlighted. how do I get the answer? 35. Calculate the concentration of...
the correct answer is highlighted. how do I get the
answer?
35. Calculate the concentration of OH' ions in a saturated Mn(OH)2 solution. The solubility product for Mn(OH)2 is 4.6 x 10-14 a. 1.0 x 10-5 M b. 2.0 x 10-5 M c. 1.6 x 10-5 M d. 3.2 x 10-5 M e. 4.5 x 10-5 M
correct answer is highlighted. what is the general process of how to get the answer? 34....
correct answer is highlighted. what is the general
process of how to get the answer?
34. Ksp for silver arsenate is 1.1 x 10-20. What is the molar solubility of AgzAsO4? a. 2.2 x 10-7 M b. 4.5 x 10-6 M . c. 6.2 x 10-8 M d. 4.1 x 10-7 M e. 1.0 x 10-10 M
the correct answer is highlighted. how do i get the answer? 36. Calculate the pH of...
the correct answer is highlighted. how do i get the
answer?
36. Calculate the pH of a saturated aqueous solution of Co(OH)2. Ksp is 2.5 x 10-16. a. 8.60 b. 8.90 c. 9.10 d. 9.20 e. 9.40
correct answer is highlighted in pink. how do i get the pH without it being 1.6?...
correct answer is highlighted in pink. how do i get
the pH without it being 1.6?
Equilibrium Constants The following equilibrium constants will be useful for some of the problems. Substance H2CO3 Substance HCOH HNO2 НОСІ (COOH)2 Constant K = 1.8 x 10-4 Ka = 4.5 x 10-4 KA = 3.5 x 10-8 K = 7.2 x 10-4 KA = 4.0 x 10-10 Ki = very large K = 1.2 x 10-2 Ka=2.5 x 10-9 Constant Ki = 4.2 x...
1. Solid calcium fluoride (CaF2) establishes the following equilibrium in solution: CaF2(s) = Ca2+(aq) + 2F-(aq)...
1. Solid calcium fluoride (CaF2) establishes the following equilibrium in solution: CaF2(s) = Ca2+(aq) + 2F-(aq) Ke = 1.5 x 10-10 A solution initially contains 2.45 g of CaF2. a. In which direction will the reaction move to reach equilibrium? Explain your reasoning b. Calculate the equilibrium concentrations of Ca2+ and F. How much CaF2 (in mg) dissolves in solution? c. Another solution initially contains 2.45 g of CaF2 and 0.0025 M NaF. What are the equilibrium concentrations of Ca2+...
The correct answers are highlighted. I do not understand how the answer came to be. Please...
The correct answers are highlighted. I do not
understand how the answer came to be. Please explain in detail.
We were unable to transcribe this imageCh. 18 Values The following values will be useful for problems in this chapter. Acid Substance or Species HF HNO2 CH3COOH НОСІ HOB HOCN HCN H2SO4 Kg = 7.2 x 104 KA = 4.5 x 10-4 K= 1.8 x 10-5 K = 3.5 10-8 Ka = 2.5 x 10-9 K = 3.5 x 104 K...
The correct answer is highlighted. I do not understand how the professor came up with this...
The correct answer is highlighted. I do not understand
how the professor came up with this answer.
Ch. 18 Values The following values will be useful for problems in this chapter. Acid Substance or Species K HF HNO2 CH3COOH HOCI HOB HOCN HCN H2SO4 Kn = 7.2 x 10-4 = 4.5 x 10-4 Ka = 1.8 x 10-5 K = 3.5 x 10-8 Ka = 2.5 x 10-9 K = 3.5 x 104 Ka = 4.0 x 10-10 Kai =...
please help me solve these problems step by step. i will rate the best answer. 9....
please help me solve these problems step by
step. i will rate the best answer.
9. Given that the Ksp for calcium fluoride [CaF2] is 3.2 x 10^-15, which of the following describes a solution that is 2.00 x 10^-5 M NaF and 2.00 x 10^5 M Ca(NO3)2? A) Q = 4 x 10^-10 and there will be a precipitate formed B) Q = 8 x 10^-10 and there will be a precipitate formed C) Q = 8 x 10^-15...
Explain the process of how to get the answer. The answer is highlighted. Ch. 18 Values...
Explain the process of how to get the answer. The
answer is highlighted.
Ch. 18 Values The following values will be useful for problems in this chapter. Acid Substance or Species HF HNO2 CH3COOH HOCI HOBr HOCN HCN H2SO4 KA = 7.2 x 10-4 Ka = 4.5 x 10-4 Ka = 1.8 x 10-5 Ka = 3.5 x 10-8 = 2.5 x 10-9 K4 = 3.5 x 10-4 Ka = 4.0 x 10-10 Kai = very large Kq2 = 1.2...
right answer is highlighted. what is the process of how to complete this answer? ID: A...
right answer is highlighted. what is the process of
how to complete this answer?
ID: A 15. Refer to Ch. 18 Values. The (OH) = 1.3 x 105 M for a 0.025 M solution of a weak base. Calculate the value of K, for this weak base. a. 5.2 x 10-5 b. 3.1 x 10-7 c. 7.7 x 10-4 d. 4.0 x 10- e. 6.8 x 10-11
the correct answer is highlighted. how do I get the
answer?
35. Calculate the concentration of OH' ions in a saturated Mn(OH)2 solution. The solubility product for Mn(OH)2 is 4.6 x 10-14 a. 1.0 x 10-5 M b. 2.0 x 10-5 M c. 1.6 x 10-5 M d. 3.2 x 10-5 M e. 4.5 x 10-5 M
correct answer is highlighted. what is the general
process of how to get the answer?
34. Ksp for silver arsenate is 1.1 x 10-20. What is the molar solubility of AgzAsO4? a. 2.2 x 10-7 M b. 4.5 x 10-6 M . c. 6.2 x 10-8 M d. 4.1 x 10-7 M e. 1.0 x 10-10 M
the correct answer is highlighted. how do i get the
answer?
36. Calculate the pH of a saturated aqueous solution of Co(OH)2. Ksp is 2.5 x 10-16. a. 8.60 b. 8.90 c. 9.10 d. 9.20 e. 9.40
correct answer is highlighted in pink. how do i get
the pH without it being 1.6?
Equilibrium Constants The following equilibrium constants will be useful for some of the problems. Substance H2CO3 Substance HCOH HNO2 НОСІ (COOH)2 Constant K = 1.8 x 10-4 Ka = 4.5 x 10-4 KA = 3.5 x 10-8 K = 7.2 x 10-4 KA = 4.0 x 10-10 Ki = very large K = 1.2 x 10-2 Ka=2.5 x 10-9 Constant Ki = 4.2 x...
1. Solid calcium fluoride (CaF2) establishes the following equilibrium in solution: CaF2(s) = Ca2+(aq) + 2F-(aq) Ke = 1.5 x 10-10 A solution initially contains 2.45 g of CaF2. a. In which direction will the reaction move to reach equilibrium? Explain your reasoning b. Calculate the equilibrium concentrations of Ca2+ and F. How much CaF2 (in mg) dissolves in solution? c. Another solution initially contains 2.45 g of CaF2 and 0.0025 M NaF. What are the equilibrium concentrations of Ca2+...
The correct answers are highlighted. I do not
understand how the answer came to be. Please explain in detail.
We were unable to transcribe this imageCh. 18 Values The following values will be useful for problems in this chapter. Acid Substance or Species HF HNO2 CH3COOH НОСІ HOB HOCN HCN H2SO4 Kg = 7.2 x 104 KA = 4.5 x 10-4 K= 1.8 x 10-5 K = 3.5 10-8 Ka = 2.5 x 10-9 K = 3.5 x 104 K...
The correct answer is highlighted. I do not understand
how the professor came up with this answer.
Ch. 18 Values The following values will be useful for problems in this chapter. Acid Substance or Species K HF HNO2 CH3COOH HOCI HOB HOCN HCN H2SO4 Kn = 7.2 x 10-4 = 4.5 x 10-4 Ka = 1.8 x 10-5 K = 3.5 x 10-8 Ka = 2.5 x 10-9 K = 3.5 x 104 Ka = 4.0 x 10-10 Kai =...
please help me solve these problems step by
step. i will rate the best answer.
9. Given that the Ksp for calcium fluoride [CaF2] is 3.2 x 10^-15, which of the following describes a solution that is 2.00 x 10^-5 M NaF and 2.00 x 10^5 M Ca(NO3)2? A) Q = 4 x 10^-10 and there will be a precipitate formed B) Q = 8 x 10^-10 and there will be a precipitate formed C) Q = 8 x 10^-15...
Explain the process of how to get the answer. The
answer is highlighted.
Ch. 18 Values The following values will be useful for problems in this chapter. Acid Substance or Species HF HNO2 CH3COOH HOCI HOBr HOCN HCN H2SO4 KA = 7.2 x 10-4 Ka = 4.5 x 10-4 Ka = 1.8 x 10-5 Ka = 3.5 x 10-8 = 2.5 x 10-9 K4 = 3.5 x 10-4 Ka = 4.0 x 10-10 Kai = very large Kq2 = 1.2...
right answer is highlighted. what is the process of
how to complete this answer?
ID: A 15. Refer to Ch. 18 Values. The (OH) = 1.3 x 105 M for a 0.025 M solution of a weak base. Calculate the value of K, for this weak base. a. 5.2 x 10-5 b. 3.1 x 10-7 c. 7.7 x 10-4 d. 4.0 x 10- e. 6.8 x 10-11
Most questions answered within 3 hours.
-
Q. A buffer solution prepared by mixing 50.00 mL of 0.200 M
acetic acid and 50.00...
asked 9 minutes ago -
PLEASE DO BOTH OF THESE IN PYTHON!!! AND MAKE SURE THAT
I CAN COPY THE CODE....
asked 8 minutes ago -
While fishing you discover two types of mullet. Some
of the mullet jump out of the water...
asked 5 minutes ago -
4. How could the Fed "finance the government's debt"? How does
that work, exactly?
5. In...
asked 11 minutes ago -
The x component of the velocity of an object vibrating
along the x-axis obeys the equation...
asked 1 hour ago -
A junction box contains two trade size 2 raceways on the left
side, and two trade...
asked 1 hour ago -
Atmospheric Mass
Venus and Earth have about the same mass and radius, but the
atmospheric pressure...
asked 2 hours ago -
5. Discuss the use of fault tree analysis (FTA) for risk
assessment (maximum one paragraph).
asked 3 hours ago -
Given that a sample of aluminium oxide has a Young's modulus of
393 GPa and a...
asked 5 hours ago -
At a certain temperature, the equilibrium constant, Kc, for this
reaction is 53.3.
H2(g)+I2(g)−⇀↽−2HI(g)Kc=53.3
At this...
asked 6 hours ago -
Question1 ) The STL provides similiar classes called stack and
queue, both of which gave functions...
asked 7 hours ago -
For Questions 1-4, assume you have 5 bits available:
1. For (positive) integers: What is the...
asked 7 hours ago