Question

Ch. 18 Values The following values will be useful for problems in this chapter. Acid Substance or Species K HF HNO2 CH3COOH HOCI HOB HOCN HCN H2SO4 Kn = 7.2 x 10-4 = 4.5 x 10-4 Ka = 1.8 x 10-5 K = 3.5 x 10-8 Ka = 2.5 x 10-9 K = 3.5 x 104 Ka = 4.0 x 10-10 Kai = very large K 2 = 1.2 x 10-2 Kal = 4.2 x 10-7 K 2 = 4.8 x 10-11 NH CH3)3N [Co(OH2)]2+ [Fe(OH2).]2+ [Fe(OH2).]3+ [Be(OH)4]2+ [Cu(OH)4]2+ НВО, (COOH)2 K6 = 1.8 x 10-5 = 7.4 x 10-5 Kn= 5.0 x 10-10 = 3.0 x 10-10 Kg = 4.0 x 10-3 = 1.0 x 10-5 K4 = 1.0 x 10-8 Ka = 6.0 x 10-10 Kal = 5.9 x 10-2 K2 = 6.4 x 10-5 K = 5.0 x 10-4 H2CO3 CH3NH2

The correct answer is highlighted. I do not understand how the professor came up with this answer.

Answer 1

Sr(OH)2 is 2 group hydroxide in periodic table. we know that 2 group element are metal and this metalic nature increases down the group Sr(stroncium)is present in lower part of the group so this highly metalic .; metalic hydroxide are basic in nature and higher the metalic nature of hydroxide ,higher the basic nature and higher the basic nature higher the solubility in water because metal hydroxide always formed ionic compound.Higher the metalic nature ,higher the ionic nature of hydroxide of metal so higher the solubility.;

6. Refer to Ch. 18 Values. Which of the following is a soluble, strong base? a. Sr(OH)2 b. NH OH c. Fe(OH)3 d. Cr(OH)3 e. Cu(OH)2

b is acid not base

c,d,e all are d block hydroxide and d block element are less metalic than 2 group element so d block hydroxide are less soluble than 2 group hydroxide