Question

What is the pH of the solution that results from adding 23.0 mL of 0.16M HCl to 23.0 mL of 0.53M NH,? Ks 1.8 10-5 pH = SubmitHF HNO CH,COOH HOCI HOBI HOCN HCN H2SO4 K = 72 x 10- K = 45 x 10 K = 1.8x10 K = 3.5x10 K -2.5 x 10 K= 3.5 x 10 K, 4.0x 10-10

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mmal ot Md melanit (m) xvolume Lm) :16 m Y 26 mL = 3.2 mmol mmd ot N 0 53 MA 23 mi: 12.19 mm ini td 12-19 md 3-2 mmd 3.2 mmel

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