We have Henderson's Equation, pH = pKa + log [ base ] / [ conjugate acid ]
pH = pKa + log [NH 3 ] / [ NH 4+ ]
pH = 9.245 + log (0.33 / 0.25 )
pH =9.245 + 0.121
pH = 9.366
We have relation, pH = - log [ H3O + ]
[ H3O + ] = 10 -pH
[ H3O + ] = 10 - 9.366 = 4.31 10 -10 M
Ratio [NH 3 ] / [ NH 4+ ] = 0.33 / 0.25 = 1.32
Consider reaction of HBr with buffer solution.
NH 3 + HBr NH 4+ + Br -
Let's use ICE table.
Moles | NH 3 | HBr | NH 4+ |
I | 0.33 | 0.13 | 0.25 |
C | - 0.13 | -0.13 | +0.13 |
E | 0.20 | 0.00 | 0.38 |
We have Henderson's Equation, pH = pKa + log [ base ] / [ conjugate acid ]
pH = pKa + log [NH 3 ] / [ NH 4+ ]
pH = 9.245 + log ( 0.20 / 0. 38 )
pH =9.245 - 0.279
pH = 8.966
We have relation, pH = - log [ H3O + ]
[ H3O + ] = 10 -pH
[ H3O + ] = 10 - 8.966=1.08 10 -09 M
Ratio [NH 3 ] / [ NH 4+ ] = 0.20 / 0.38 = 0.526
From above calculations we can answer given statements.
True A. The number of moles of NH3 will decrease.
True B. The number of moles of NH4+ will increase.
False C. The equilibrium concentration of H3O+ will decrease.
False D. The pH will increase.
False E. The ratio of [NH3] / [NH4+] will remain the same.
We have Henderson's Equation, pH = pKa + log [ Salt ] / [acid ]
pH = pKa + log [NO 2- ] / [ HNO2 ]
pH = 3.15 + log ( 0.25 / 0.33 )
pH = 3.15 - 0.121
pH = 3.03
We have relation, pH = - log [ H3O + ]
[ H3O + ] = 10 -pH
[ H3O + ] = 10 -3.03 = 9.35 10 -4 M
Ratio [ HNO 2 ] / [ NO 2 - ] = 0.33 / 0.25 = 1.32
Let's use ICE table.
Moles | HNO 2 | NO 2 - |
I | 0.33 | 0.25 |
C | +0.13 | - |
E | 0.46 | 0.25 |
We have Henderson's Equation, pH = pKa + log [ Salt ] / [acid ]
pH = pKa + log [NO 2- ] / [ HNO2 ]
pH = 3.15 + log ( 0.25 / 0.46 )
pH = 3.15 - 0.265
pH = 2.99
We have relation, pH = - log [ H3O + ]
[ H3O + ] = 10 -pH
[ H3O + ] = 10 -2.99 = 1.04 10 -3 M
Ratio [ HNO 2 ] / [ NO 2 - ] = 0.46 / 0.25 = 1.84
From above calculations we can answer given statements.
False A. The number of moles of HNO2 will decrease.
False B. The number of moles of NO 2 - will increase.
True C. The equilibrium concentration of H3O+ will increase
True D. The pH will decrease.
False E. The ratio of [ HNO 2 ] / [ NO 2 - ] will remain the same.
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