Question

e an average kinetic energy proportional to the tempera d. all of the above onal to the temperature in kelvin 2. Convert 600 mm Hg to atm. a. 0.789 atm b. 4.24 x 10 atm C. 38.0 atm d. 18.6 atm 760 mm Hg = lat . then 600m Hg = 1XGOC =0.78 3. A sample of gas has an initial volume of 3.95 L at a pressure of 705 mm Hg If the volume of the gas is increased to 5.38 L, what is the pressure (al constant temperature)? - D P-705 mm Hg M TV a. 517.6 mm b. 518 mm v. = 3.95Lt V2-5.38L C. 960 mm d. 564 mm P2=? PV,=P₂ V₂ P = Povi = 705x3,95 =1517.6m 4. A 3.00 L gas sample in a cylinder with a freely moveable piston is initially at 25.0°C. What is the volume of the gas when it is heated to 145° C (at constant pressure)? a. 1.82 L b. 4.21 L C. 0.440 L d. 14.8L 35 mm Hg. The volume is decreased to AC 488 mland the temperature is incre e has an initial volume of 50,0 mL, an initial temperature of 5. A gas sample has an initial volume of 500 ml Vi=30 350° C. and an initial pressure of 735 mm Hg. The volume i and the temperature is increased to 72.5° C. What is the final 1, -250 - Pi=735 resource had 2 ch.2018 7 Johwede P2=345.5X1125750 216/20. 10:01 PM 48.8X308845 him of pressure? a. 845 mm Hg PAN=2 PX480_345-5 T 135X50 0082-40.6 tps://learning semo.edu/pluginfile.php/3213584/mod resource

Answer 1

Palatri Pe latry Since , piston is freely morable. It will adjust to such position when internal pressure (P) equals atomospheric pressure le. 1 atm. of the gas will be constant Hence, p According to is Charle's low Kelvin temperature [/t = constant & x= Volume At constant ? 4.208 L or VF = 418*3 L= 298 Loption ® is comect. Vole of gas = 4:21 L I guitial conditions Find Conditious 735 mm Hg Pressure Some 308 K Volume Temperature 48.8 ml 345.5k . According to Ideal gas equation (PV/T = constant] in 735 x 5o = PE (in um Hg) x 48.8. oss Pf = 735 x 50 x 345.5_-_844.76 mm Hg 49.8 735 xso 308 34S.S 48.8 x 308 option ② is comect. Find pressure = 845 mm Hg - in or 760 mm Hg = 1 mm Hg = Goo mm Hg = 1 atra 1/760 atu 600/760 atm = 0.789 atro option ® is correct re. 0.789 atm

6. According to Boyle's law, PV = constant at constant T ise P;V; - PE VE or, 705 X 3.95 = or Pr = 705 x 3.95 S.38 PE (in mm Hg) x 5:38 = 517.6 mm Hg I Option ® is connect. Pressure final = 517.6 mm Hg)