Question 2 10 Points Use the following equation for questions 2-9. 2 C8H18 + 25 02...
ACCOUNT Question 4 10 Points How many moles of oxygen are required to produce 200.0g H2O? BLANK-1 mol O2 BLANK-1 Add your answer Question 5 10 Points How many grams of oxygen are needed to produce 250.0 g of CO2? BLANK-1 g 02 BLANK-1 Add your answer Question 6 10 Points How many grams of C8H18 are needed to form 4.00 L of CO2 gas? BLANK-1 8 C8H18 BLANK-1 Add your answer Question 7 10 Points How many liters of...
The combustion of octane (C8H18) in oxygen proceeds as follows 2 C8H18(g) + 25 O2(g) ---> 16 CO2 (g) + 18 H2O(l) How many moles of CO2are produced when 5.0 moles of octane, C8H18, is burned in 5.0 moles of oxygen?
the complete combustion of octane , C8H18, a component og gasoline, proceed as 2 C8H18 +25 O2 = 16 CO2 + 18H2O. a) how many moles of CO2 are produced when 1.50 mol octance reacted? b) how many grams of water produced in this reaction? c)how many moles of oxygen required to form 90.0 g water?
According to the following combustion reaction of gasoline (Octane), how many moles of C8H18 needs to be reacted to produce 16 moles of CO2? C8H18 (l) + 25/2 O2 (g) → 8CO2 (g) + 9 H2O
Burning octane is: 2 (C8H18) + 25 (O2) ......... 16 (CO2) + 18 (H2O) How many moles of oxygen would you need to burn 2.37 moles of octane?
Given the following: 2 C8H18 + 25 O2 ====è 16 CO2 + 18 H2O Find the limiting reagent for making CO2 from 35.4 Moles C8H18 and 145 moles O2. Then find the grams excess reagent left at the end of the reaction
Use this balanced equation to answer the following stoichiometry problem. 2C3H18(1) + 25 O2(g) →16 CO2(g) + 18 H2O(g) The molar masses in grams are: C8H18 = 114; O2 = 32; CO, = 44; H20 = 18. If you burn 72.9 g of octane, how many liters at STP of CO2 are produced? O 179 L 129 L 83.5L 115L
14. For the following problem, use the following chemical equation: C8H18 (1) + O2(g) CO2(g) + H2O(g) a. Balance the chemical equation. b. How many moles of oxygen are needed to fully react 837.4 grams of C8H18?
The combustion of octane, C8H18, proceeds according to the reaction 2 C8H18(l) + 25 O2(g) --> 16 CO2(g) + 18 H2O(l) If 442 mol of octane combusts, what volume of carbon dioxide is produced at 20.0 ?C and 0.995 atm?
2 C8H18 (l) + 25 O2 (g) ----> 16 CO2 (g) + 18 H2O (g)(OR 2 C8H18 (l) + 25 O2 (g) right arrow 16 CO2 (g) + 18 H2O (g))Use the following conversions: 1 mol = MW in g (2 d.p.) = 22.414 LAll gases are at STP. How many liters of CO2 would be produced from the reaction of 5.0 L of C8H18 with 55 L of O2?Theoretical yield of CO2 from 5.0 L C8H18 = _____________Theoretical yield...