![Data[2]: Mass of fresh soap Mass of cured soap 314.30.3 267 19 9 PH: PH: 9.0 10.25 Date: Feb 7 th 2020 Date: March 6th 2020 C](http://img.homeworklib.com/questions/08f6aba0-d4fb-11eb-8676-e78ef1d582c2.png?x-oss-process=image/resize,w_560)
Homework Answers
The answer to this question is quite simple
We have to find out the loss on drying in percent
And rate of evaporation
We have Initial mass = 314.30
And final mass = 267.19 gram.
Difference = 314.30-267.19 = 47.11 gram
So% loss = (47.11/314.30) ×100
=14.99 %
Now average rate of evaporation
The evaporated weight is 47.11 gram
And total time required for it is from feb 7 to march 6 is 28 days
So rate of evaporation is
Mass evaporated /time taken
=47.11/28 day
= 1.68 gram /day
So rate of evaporation of water from soap is 1.68 gram/day
I hope this helps. If you have any query or want more detailed explanation, feel free to ask in the comments section below.
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Data[2]: Mass of fresh soap Mass of cured soap 314.30.3 267 19 9 PH: PH: 9.0...
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the data is coming directly from
professor and i think she made a mistake because after I work out
problem I get theoritcal yeild of 0.850 grams
CaCO3 but the experiment actual yield is 8.322 grams (work out
question 12 )
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