Question

A solution contains Al3+ and Co2+. The addition of 0.3555 L of 1.823 M NaOH results in the complete precipitation of the ions as Al(OH), and Co(OH),. The total mass of the precipitate is 22.78 g. Find the masses of Alº+ and Co2+ in the solution. mass of A13+: 09 mass of Co2+: g

Answer 1

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Given mole of NOOH = MXV(L) = 0.3555 Lx 1.823M=0.648 | mole moss of precipitate = 22.78 4me Let mass of AlloH)2 3 2 gm - mass of coloha > (22-78-2) gm mole of a gm. as 304 required so 3x mole Allon)3 78gm/mol. 78 mole of 22-78-7 gm as zou required 2(22-78- mole Cocond 92-94 gr/mol 92.94 3x 45-56-24 3 0.648 mole 78 92.g4 0.03846 at 0.490 – 0.02154 - 0,648 0,490+ 0.01696x= 0.648 0.01696%= 0.158 a=g. 32gm mass of Al(OH)3 = 9.32 gm, mass of COCOH), = 13:46gm moleq Al(OH), = 9:32 - 0.1195 mole of = 13.46 = 0.145 mol! 78 Colon), 92.94 37 weight of Albord = 0-1195 x 27 = 0.145_X58.94 27 reight of 6827= D.14sma 8.55 gm = 3.23% 2 sdanned with CamScanner