Question

have united attempts/There is no attempt penalty Question (6 points) See page 236 1st attempt See Periodic Table See Hint An insulated container is used to hold 48.5 g of water at 39.8°C. A sample of copper weighing 7.60 g is placed in a dry test tube and heated for 30 minutes in a boiling water bath at 100.0°C. The heated test tube is carefully removed from the water bath with laboratory tongs and inclined so that the copper slides into the water in the insulated container. Given that the specific heat of solid copper is 0.385 J/(g.°C), calculate the maximum temperature of the water in the insulated container after the copper metal is added. SUBMANS WE < 16/16 > 8 OF 16 QUESTIONS COMPLETED

Answer 1

Here mass of water in 40.5g unsulated tank = 485g Temperature = 39.8°C Specific heat of wales - 4 1845 / goc marg copper piece = 7.60 g Temperature = 100°c [Because this copperpiece is dipped in 100°c boiling tualer specifichent = 0.385 J/g °c bath by a test tupe for 30 minutes so it will achiewe 2000 temperature. How let us consider quelitnum final leuperature = Tee. how sime copper at 100% so heat is lost by Copper completely gained by wake so copper = Quater. que = mcu AT 7.60 x 0.385 (+100 -Tep) Qw = mw (w DT = 48.5 * 4.184X (Tex - 39.8) Dcu= Qw 7.60 70.385(100-Tep = 48.5x4184 (tep-39.8) 1.442 - 0.01442 Teg = Tee – 39.8 41. 242 101442 Teq = 40.656 x 40.7°C maximum temperature of water attained a 40.7°C 1