HNO2 = H+ + NO2-
I 0.1 0 0
C -X +X +X
E (0.1-X) +X +X
Ka = 4.5 x 10-4
Ka = (H+)(NO2-)/(HNO2)
4.5 x 10-4 = X2 / (0.1-X)
X = -0.0069 or 0.0069
So H+ = 0.0069
pH = -log(H+)
pH = -log (0.0069)
pH = 2.1611 = 2.17
so option C is correct
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