Question

I think I calculated the precipitate correctly. I got 1.151g. I did this by adding the g of cobalt synthesize product to the g of AgNO3.

I just cant figure out how to solve for B

PART F (GRAVIMETRIC ANALYSIS) 53.589 Gravimetric analysis is a technique used to quantitatively determine the amount of an analyte based on its mass. In this particular case, a solution of silver nitrate will be added to a solution of the synthesized compound and the counterion chloride ions will precipitate as silver chloride. Any ligand chloride ions should not precipitate. The mass of silver chloride that precipitates can then be converted into the number of chloride counterions per formula unit of the synthesized compound. Procedure: 1. Place approximately 0.3 g of the synthesized product into a 250-ml flask. Record the actual mass used in the lab notebook. SD2 2. Add 70 mL DI H20 and stir until completely dissolved. 3. Add 5.0 mL of 1 M AgNO, and stir for an additional 2 minutes. 4. Measure the mass of a clean, dry watch glass. 57.94/ 5. Measure the mass of a filter paper..699 6. Filter the solution/precipitate using the filter paper from above. 7. Dry the precipitate by pulling air through the funnel for an additional 10 minutes. 8. Transfer the precipitate and filter paper to the watch glass. 9. Place the watch glass in the drying oven for 60 minutes. 10. Measure the mass of the watch glass/filter paper/precipitate. 52466 Analysis: 11. Show the following calculations in the lab report: A. Calculate the mass of the precipitate. B. Calculate the % w/w of chloride in the synthesized product. C. Calculate the theoretical % w/w chloride in the following compounds usin atomic masses from the Periodic Table: [Co(NH3).] CI [Co(NH3).] Cl2 [CO(NH3)6] Cl3 [Co(NH3)6] CI4 2. In the lab report, calculate the % error from the expected result and discu meaning of the results and any possible errors.

Answer 1

Crowed n) yas te precipitate = lass of coatch glass / Soltes paper / Precipitate mass of wootch glass - Mass of filter perper B) = 52.466 - 51-341 - 0.699 = 0.426g. % w/w of chloride in synthesized podud = mass of cl x100 many soudion Preupitate Agd = 0.4 269

143:32 gt of Ag I contains 35.45 2 of chloride So, 0.426 g of Azel will conteun = 25.45 +0.426 = 0.1057 chlerede ton % w/w = 0.105 0302 x 100 = 34.89 % c) [ conne, ce Molar mass of [colnn, Ice = 196-383 almal . . " l = 35.43 g/mol 1 w/w of chloride = 35.453x100 = 18.04% 196.383 [co (N) Il Molos mass of [co (Nh) Icd = 231.836 glonal "" = 70.906 g/mol wler chloride = 70.906 x lod = 30.58% 231-836 [co (NB) Id Holar mass of [co (Nh) Ich = 267. 289 g/mol " a = 106.359 g/mol (w/w chloride = 106. 359 xloo = 39.79.7 267.289

[CO(Nh) Ilu Polo, cм с. Гco (м.), 24, - Зох. 2 ч. /va0 , , , а = 19, 3/2 / mo (0) / cito it de = 197 - 8/2 x 100 = 16. 8V 7. 20. 2ч 2