The following thermochemical equation is for the reaction of hydrogen chloride(g) with ammonia(g) to form ammonium...

Question

Question

Answer 1

Answer #1

Solution :

Part A) The given reaction is,

HCl (g) + NH3 (g) = NH4Cl (s) , ΔH = -176 kJ/mol

Molar mass of HCl = 36.5 g mol-1

Since, 176.5 kJ heat is obtained from 36.5 g HCl

Hence, 51.9 kJ of heat required

= 51.9 kJ x 36.5 g / 176.5

= 10.73 g

Part B) The reaction of HBr and Cl2 is given as,

2HBr + Cl2 = 2HCl + Br2 , ΔH = -81.1 kJ/mol

Molar mass of HBr = 80.91 g mol-1

Since, 2 mol (2 x 80.91 g) HBr produces 81.1 kJ heat

Hence, 16.4 g will produces

= 16.4 g x 81.1 kJ / (2 x 80.91 g) = 8.219 kJ

= 8.22 kJ

Thus, 8.22 kJ heat is evolved.

Answer 2

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