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The following thermochemical equation is for the reaction of ammonium chloride(s) to form ammonia(g) and hydrogen...

The following thermochemical equation is for the reaction of ammonium chloride(s) to form ammonia(g) and hydrogen chloride(g). NH4Cl(s) NH3(g) + HCl(g) H = 176 kJ How many grams of NH4Cl(s) would be made to react if 49.8 kJ of energy were provided?

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Answer #1

NHull ts1 An: 176 kJ/mol NH₂ (g) + Hill (9) (g) + Hu hrat mobs of NHull require AH 49.8KJ 176 kJ/mol 0.283 moles Mass : Moler

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