0.0825 m NaCl, 0.050 m KCl, 0.050 M Na2SO4, 0.055m Ca (NO3) 2, 0.050 m Na3PO4.
1)
delta Tb = i x Kb x m
here Kb value is same for all . boiling point depend on i x m value.
a) NaCl = 2 x 0.0825 = 0.165
b) KCl = 2 x 0.050 = 0.100
c) Na2SO4 = 3 x 0.050 = 0.150
d) Ca(NO3)2 = 3 x 0.055 = 0.165
e) Na3PO4 = 4 x 0.050 = 0.200
order of boiling point :
KCl < Na2SO4 < NaCl < Ca(NO3)2 < Na3PO4 .
2)
osmatic pressure = i x M x S x T
a) NaCl :
osmatic pressure = 2 x 0.0825 x 0.0821 x 298
= 4.04 atm
b)
KCl :
osmatic pressure = 2 x 0.05 x 0.0821 x 298
= 2.45 atm
c)
Na2SO4 :
osmatic pressure = 3 x 0.05 x 0.0821 x 298
= 3.67 atm
d)
Ca(NO3)2 :
osmatic pressure = 3 x 0.055 x 0.0821 x 298
= 4.04 atm
e) Na3PO4 :
osmatic pressure = 4 x 0.05 x 0.0821 x 298
= 4.89 atm
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