Hi there, i am so sorry for part-b, since this require Garcia mini lecture video posted on Friday March 20th on your university website, which is inaccessible for me. So i am gonna answer part-a now!
The given HNMR spectrum was complex and there is no further expanded spectral regions for me by you, hence i did a simulation on my lappy. The results are according to n+1 rule
8.1257 ppm, doublet, 1H due to Ha proton (due to coupling with adjacent Hb proton - 1+1 =2, doublet )
6.5295 ppm, doublet, 1H due to Hb proton (due to coupling with adjacent Ha proton - 1+1 =2, doublet )
4.32 ppm, quartet, 2H , due to Hc proton (due to coupling with adjacent Hd proton - 3+1 = 4, quartet)
1.3979 ppm, triplet, 3H, due to Hd proton (due to coupling with adjacent Hc proton - 2+1 = 3. triplet)
You may find coupling constants along with all other required relevant data in simulated HNMR spectrum below, and also attaching CNMR if incase you wanna compare this with your one!
Hope this helped you!
Thank You So Much!
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b. Assign the indicated protons (a, b,c,d) in the Wittig product H NMR (CDC13, 60 MHz),...
9. H NMR analysis - 2 points total a. Assign only the aldehyde proton (Ha) in the H NMR spectrum of 9-anthraldehyde (CDC13, 60 MHz). The aromatic protons are overlapping (9-7.5 ppm) and it is challenging to individually assign them all (0.25 point) Havo Aromatic protons 11.5297 POCO 6- -8.9060 -8.6782 -8.1397 -7002 2.001.02 6.03 90 115 11.0 105 10 0 95 45 40 35 3.0 85 80 751 7065 60 55 50 Chemical Shift (ppm)