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If 6.24 moles of HCl are consumed, calculate: a) the number of grams of calcium hydroxide consumed 231.2 b) the number of gra
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Answer #1

Sol 2.

As Combustion Reaction of propane , C3H8 :

C3H8 + 5O2 -----> 3CO2 + 4H2O  

As Mass of C3H8 = 20 lb

= 20 × 453.592 g  

= 9071.84 g  

Molar Mass of C3H8 = 44.1 g/mol

So , Moles of C3H8 = 9071.84 g / 44.1 g/mol

= 205.7106 mol

At STP , 1 mol = 22.414 L  

Therefore , Liters of propane gas , C3H8 released at STP

= 205.7106 × 22.414 L

=    4610.80 L  

Now , From reaction , Moles of CO2 = Moles of C3H8 × 3

= 205.7106 mol × 3  

= 617.1318 mol

Therefore , Liters of CO2 gas produced at STP

= 617.1318 × 22.414 L

=    13832.39 L  

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