Question

Consider the following reaction in basic solution: Cr(OH)₃  + ClO^- --> Cl₂ + CrO₄^2-

Which of the following statements is/are correct?

1. The oxidizing agent is Cr(OH)₃.

2. The oxidation number of the atom being reduced changes from 0 to -2.

3. The oxidation number of the atom being oxidized changes from +3 to +6.

4. When the equation is balanced, the species OH^- appears on the right hand side of the equation.

• A. 3 only
• B. 3 & 4 only
• C. 1 only
• D. 1 & 2 only
• E. 4 only

Answer 1

Son=> Consider the following reaction in bagie solution CY COH)3 + C10 --> cl2 + cron which of the following statements is correct. =) correct option is (A) i.e. 3 only. The osudation number of the atom being orádized changes from t3 to t6. 7- +3 -2 +1 +1 -1 Eseplanation! Bulunce this equation in busie solution, is write the unbalanced equcetion. Cr COH)3 +.clo - clateria ii) Assign ogeidation numbers for each citoms in equation crcolt clo clattor 1 1: Ovidurion - 1. Reduction ouudising agent - clo --(species takes place Reduction Reducing agent - CrLOH)2 C species takes place or udation) C Hence frost Stetement incorrect. Mis Write Separude oridation halt reuehion and reduction half reaction. +3 -2 +1 +6-22- oridation: CCOH)3 - croe change oxy? no. +3 to +6.Chence 3Statement is correct) Reduction - Glo - Çiz+! Change omu? no. ti to o CHence 2" Statement inconecta

iv) Bulunee other clums esecelt hydrogen and Ozeygen Crotte crou 2clo cl . W Balunce the Onygen chom by adding the molecules. CrCOH)2 + the coon 2 clo Cl2 + 2tho vij Balance hydrogen atoms by adding H7 cpoulins' Cr comOz + tho — Cool? 7567 2 clo.+4h7 clatatho viis Reachon is basic medium, add one oħ ion to each side for every Htion, of ions added both side to balance Charge and atoms. Combine ost 4 Ht ions on Same side to form water. crcolz + the +501 crosstho 1 2c10+ 4400 cl2 + 2tho +404 viii) Po balance charge add electrons, on respective side cr collz + the + 500 crortstho 3 ē 2 clo+ 4th of 4 Cl2 + 2the +404 ix] to eliminate eletrons , multiply by 4 to ovudbion half reaction and multiply by 3 to reduction half reaction

4X Corcohat the +504 Crossthotze. 3x (2c10+4 400 + 40 (2+2tho +4055 Equctions becomes 4 Cr COH)2 + 4th0 + 20 - 4 croz +20 tot 127 6 c10 + 12 tho + 12 ē3cl2 + 6tho + 1204 x) Add both half reactions together c Combine both recetion) 4 Cr Col₃ + 6(1016450 + wont le 460oh² + 3Cl2 + 26tho + 125€ + 1200 xiy same species on opposite side are cunealed.equation 8 OH 10 to ecomes 4 Cr Col₃ + 6(10 + 80H 4 cro? +3clat 10420 This is a bulunce equcetion.. when the equation is balanced, the species of appears on the left hand side of the equation. Hence statement 4 is incorrect. xiy Hence allording po this bulance equation correct option is CA) i.e. 3 only. 1.2. Statement 3 is correct only