correct answer is highlighted.
what is the process of how to find the value of the ionization
constant of the acid?
this is my work so far...
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what is the process of how to find the value of the...
right answer is highlighted. what is the process of how to complete this answer? ID: A...
right answer is highlighted. what is the process of
how to complete this answer?
ID: A 15. Refer to Ch. 18 Values. The (OH) = 1.3 x 105 M for a 0.025 M solution of a weak base. Calculate the value of K, for this weak base. a. 5.2 x 10-5 b. 3.1 x 10-7 c. 7.7 x 10-4 d. 4.0 x 10- e. 6.8 x 10-11
Explain the process of how to get the answer. The answer is highlighted. Ch. 18 Values...
Explain the process of how to get the answer. The
answer is highlighted.
Ch. 18 Values The following values will be useful for problems in this chapter. Acid Substance or Species HF HNO2 CH3COOH HOCI HOBr HOCN HCN H2SO4 KA = 7.2 x 10-4 Ka = 4.5 x 10-4 Ka = 1.8 x 10-5 Ka = 3.5 x 10-8 = 2.5 x 10-9 K4 = 3.5 x 10-4 Ka = 4.0 x 10-10 Kai = very large Kq2 = 1.2...
The correct answer is highlighted. I do not understand how the professor came up with this...
The correct answer is highlighted. I do not understand
how the professor came up with this answer.
Ch. 18 Values The following values will be useful for problems in this chapter. Acid Substance or Species K HF HNO2 CH3COOH HOCI HOB HOCN HCN H2SO4 Kn = 7.2 x 10-4 = 4.5 x 10-4 Ka = 1.8 x 10-5 K = 3.5 x 10-8 Ka = 2.5 x 10-9 K = 3.5 x 104 Ka = 4.0 x 10-10 Kai =...
The correct answers are highlighted. I do not understand how the answer came to be. Please...
The correct answers are highlighted. I do not
understand how the answer came to be. Please explain in detail.
We were unable to transcribe this imageCh. 18 Values The following values will be useful for problems in this chapter. Acid Substance or Species HF HNO2 CH3COOH НОСІ HOB HOCN HCN H2SO4 Kg = 7.2 x 104 KA = 4.5 x 10-4 K= 1.8 x 10-5 K = 3.5 10-8 Ka = 2.5 x 10-9 K = 3.5 x 104 K...
I need the highlighted parts, and check if what I did is correct. Thanks! I. Equilibrium...
I need the highlighted parts,
and check if what I did is correct. Thanks!
I. Equilibrium Glacial CH3COOH Final buret reading 46 Moles acetic acid 0.0524 used (show work) Molarity of solution (show work) Initial buret reading 49 0.524 mL acetic acid used 3 mL H30 1eq 1.4125 x 10-3 pH measured 2.85 Using appropriate concentrations, complete the "I", "C", "E" table below [CH3COO- [CH:COОH] 0.524 [H:О"] Initial concentrations +1.4125x10-3 1.4125x10-3 +1.4125x10-3 1.4125x10-3 Change Equilibrium Conc Calculate the value of...
please help. 1. (3 polnts) A 0.0730 M solution of a monoprotic acid is 1.07 %...
please help.
1. (3 polnts) A 0.0730 M solution of a monoprotic acid is 1.07 % ionized. What is the pH of the solution? a. b. Calculate the K, of the acid. 2. (2 points) The pH of a 0.025 M solution of a monoprotic acid is 3.21. What is the Ka value for the acid? 3. (2 points) Determine the percent ionization of a 0.0028 M HA solution. (K, of HA 1.4 x 10") 4. (4 points) Lysine is...
Determine the volume you would need of each solution (acid/base and conjugate) to make a buffer...
Determine the volume you would need of each solution (acid/base and conjugate) to make a buffer with a specific pH. Please only use the acids, bases and salts from the table on page 87 in the lab manual. See below for assigned values, each person will be calculating volumes needed for an acidic buffer and a basic buffer. Chart from page 87 List 0.10 M CH,NH, 9.75 the 0.10 M NHỰC H. " List E 0.10 M HCOOH K -...
44. A 0.10 M solution of a weak monoprotic acid has a hydronium-ion concentration of 4.6...
44. A 0.10 M solution of a weak monoprotic acid has a hydronium-ion concentration of 4.6 x 10 *M. What is the acid- ionization constant, Ka, for this acid? 2.2.1 x 10-2 b. 3.2 * 10-3 C.4.6 x 104 d. 2.1 x 10-6 e.5.5 x 10-5
(3 points) A 0.0730 M solution of a monoprotic acid is 1.07% ionized. What is the...
(3 points) A 0.0730 M solution of a monoprotic acid is 1.07% ionized. What is the pH of the solution? Calculate the Ka of the acid. (2 points) The pH of a 0.025 M solution of a monoprotic acid is 3.21. What is the Ka value for the acid? (2 points) Determine the percent ionization of a 0.0028 M HA solution. (Ka of HA = 1.4 x 10-9) (4 points) Lysine is triprotic amino acid (separately loses three H’s in...
correct answer is highlighted in pink. how do i get the pH without it being 1.6?...
correct answer is highlighted in pink. how do i get
the pH without it being 1.6?
Equilibrium Constants The following equilibrium constants will be useful for some of the problems. Substance H2CO3 Substance HCOH HNO2 НОСІ (COOH)2 Constant K = 1.8 x 10-4 Ka = 4.5 x 10-4 KA = 3.5 x 10-8 K = 7.2 x 10-4 KA = 4.0 x 10-10 Ki = very large K = 1.2 x 10-2 Ka=2.5 x 10-9 Constant Ki = 4.2 x...
right answer is highlighted. what is the process of
how to complete this answer?
ID: A 15. Refer to Ch. 18 Values. The (OH) = 1.3 x 105 M for a 0.025 M solution of a weak base. Calculate the value of K, for this weak base. a. 5.2 x 10-5 b. 3.1 x 10-7 c. 7.7 x 10-4 d. 4.0 x 10- e. 6.8 x 10-11
Explain the process of how to get the answer. The
answer is highlighted.
Ch. 18 Values The following values will be useful for problems in this chapter. Acid Substance or Species HF HNO2 CH3COOH HOCI HOBr HOCN HCN H2SO4 KA = 7.2 x 10-4 Ka = 4.5 x 10-4 Ka = 1.8 x 10-5 Ka = 3.5 x 10-8 = 2.5 x 10-9 K4 = 3.5 x 10-4 Ka = 4.0 x 10-10 Kai = very large Kq2 = 1.2...
The correct answer is highlighted. I do not understand
how the professor came up with this answer.
Ch. 18 Values The following values will be useful for problems in this chapter. Acid Substance or Species K HF HNO2 CH3COOH HOCI HOB HOCN HCN H2SO4 Kn = 7.2 x 10-4 = 4.5 x 10-4 Ka = 1.8 x 10-5 K = 3.5 x 10-8 Ka = 2.5 x 10-9 K = 3.5 x 104 Ka = 4.0 x 10-10 Kai =...
The correct answers are highlighted. I do not
understand how the answer came to be. Please explain in detail.
We were unable to transcribe this imageCh. 18 Values The following values will be useful for problems in this chapter. Acid Substance or Species HF HNO2 CH3COOH НОСІ HOB HOCN HCN H2SO4 Kg = 7.2 x 104 KA = 4.5 x 10-4 K= 1.8 x 10-5 K = 3.5 10-8 Ka = 2.5 x 10-9 K = 3.5 x 104 K...
I need the highlighted parts,
and check if what I did is correct. Thanks!
I. Equilibrium Glacial CH3COOH Final buret reading 46 Moles acetic acid 0.0524 used (show work) Molarity of solution (show work) Initial buret reading 49 0.524 mL acetic acid used 3 mL H30 1eq 1.4125 x 10-3 pH measured 2.85 Using appropriate concentrations, complete the "I", "C", "E" table below [CH3COO- [CH:COОH] 0.524 [H:О"] Initial concentrations +1.4125x10-3 1.4125x10-3 +1.4125x10-3 1.4125x10-3 Change Equilibrium Conc Calculate the value of...
please help.
1. (3 polnts) A 0.0730 M solution of a monoprotic acid is 1.07 % ionized. What is the pH of the solution? a. b. Calculate the K, of the acid. 2. (2 points) The pH of a 0.025 M solution of a monoprotic acid is 3.21. What is the Ka value for the acid? 3. (2 points) Determine the percent ionization of a 0.0028 M HA solution. (K, of HA 1.4 x 10") 4. (4 points) Lysine is...
Determine the volume you would need of each solution (acid/base and conjugate) to make a buffer with a specific pH. Please only use the acids, bases and salts from the table on page 87 in the lab manual. See below for assigned values, each person will be calculating volumes needed for an acidic buffer and a basic buffer. Chart from page 87 List 0.10 M CH,NH, 9.75 the 0.10 M NHỰC H. " List E 0.10 M HCOOH K -...
44. A 0.10 M solution of a weak monoprotic acid has a hydronium-ion concentration of 4.6 x 10 *M. What is the acid- ionization constant, Ka, for this acid? 2.2.1 x 10-2 b. 3.2 * 10-3 C.4.6 x 104 d. 2.1 x 10-6 e.5.5 x 10-5
correct answer is highlighted in pink. how do i get
the pH without it being 1.6?
Equilibrium Constants The following equilibrium constants will be useful for some of the problems. Substance H2CO3 Substance HCOH HNO2 НОСІ (COOH)2 Constant K = 1.8 x 10-4 Ka = 4.5 x 10-4 KA = 3.5 x 10-8 K = 7.2 x 10-4 KA = 4.0 x 10-10 Ki = very large K = 1.2 x 10-2 Ka=2.5 x 10-9 Constant Ki = 4.2 x...
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