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U Np Pu Am Cm Bk Cf Es Es Fm M If the heat of combustion of carbon monoxide (CO) is --283.0 in order to release 2,500 kJ of e
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Answer #1

heat of combustion of CO = -283 KJ/mol

CO = 28 g/mol

28 g CO release 283 KJ

X g CO release 2500 KJ

X = 2500 x 28 / 283 = 247.3 g

mass of CO required = 247.3 g

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