Moles of Pb = (0.586 g) / (207.2 g/mol) = 0.0028 mol
weight of oxygen in lead oxide = 0.677 g - 0.586 g = 0.091 g
moles of Oxygen = (0.091 g) / (16 g/mol) = 0.00568 mol
Simplest mol ratio
Pb = (0.0028 mol) / (0.0028 mol) = 1
O = (0.00568 mol) / (0.0028 mol) = 2
Empirical formula is: PbO2
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