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If 0.586 grams of lead reacted with oxygen and 0.677 grams of the lead oxide is formed, what is the empirical formula of the

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Answer #1

Moles of Pb = (0.586 g) / (207.2 g/mol) = 0.0028 mol

weight of oxygen in lead oxide = 0.677 g - 0.586 g = 0.091 g

moles of Oxygen = (0.091 g) / (16 g/mol) = 0.00568 mol

Simplest mol ratio

Pb = (0.0028 mol) / (0.0028 mol) = 1

O = (0.00568 mol) / (0.0028 mol) = 2

Empirical formula is: PbO2

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