If 41.6g of chromium is fully reacted with oxygen to produce 60.8g of chromium oxide, what...

Question

Question

If 41.6g of chromium is fully reacted with oxygen to produce 60.8g of chromium oxide, what is the empirical formula of the chromium oxide

Answer 1

Answer #1

Mass of Cr₂O₃ =151.99 g/mol

We know atomic mass of oxygen =16g

Mass of oxygen in chromium oxide =(16×3/151.99 )×60.8

=19.20g

Percentage of Chromium= (41.6/41.6+19.20)×100%

=68.42%

Percentage of oxygen = (19.2/41.6+19.2)× 100%

=31.57%

Now rounding off to simplest whole no ratio

Chromium =2

Oxygen= 3

Therefore empirical formula = Cr₂O₃

Answer 2

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