Question

A0.500-g sample of tin foil reacted with oxygen to give 0.635 g of product. Calculate the empirical formula of the tin oxide. Refer to Example Exercise 1 Record your numbers to 3 significant figures. Do not use exponential notation or subscripts in your answers. a) The mass of oxygen used in the reaction is b) The number of moles of tin is moles and the number of moles of oxygen is moles. c) Using their ratio of number of moles, this yields an empirical formula of

Answer 1

Sn + O2 Sn Ox : mass of Sn + mass of O₂ = mass of SnOn - (a) : mass of O₂ used = 0.635 g -0.500 g = 0.135 g Mw of tio (Sn) = 118.71 g/mol :: (b) no. of moles of tin = 0. Sov g = 0.0042 12 mol (18.71 g/mol - 10.00421 mell and no. of moles of O2 = = 0-135 g 32g/mol 0.004219 mol =10.00422 moll (C) 1 mol sn reacts with a mol O2 3 signifig cant figures : 0.00421 X 2 = 0.00422 - 2 x = 2 -:|x = 21 . Empirical formula is sno. I