Question

Mass of empty crucible with cover Mass of crucible, cover, and tin Mass of crucible, cover, and sample after reaction and prolonged heating 19.66 g 21.76 g 22.33 g A similar experiment was used to determine the empirical formula of an oxide of tin (Sn). Use the data provided to answer the following question. Calculate the number of moles of tin in the oxide of tin sample.

Answer 1

Answer:

1. Amount of Sn = 21.76 g - 19.66 g = 2.1 g; Molar mass of Sn = 118.71 g/mol

Moles of Sn used = 0.0177 moles

Two most common oxides of Sn are SnO (134.71 g/mol) and SnO₂ (150.71 g/mol)

Hence, Amount of SnO_x obtained = 22.33 - 19.66 = 2.67 g

I. With SnO = 0.0177 x 134.71 = 2.38 g

II. With SnO₂ = 0.0177 x 150.71 = 2.667 g

Hence, SnO₂ is more nearer to the sample weight.

Oxide form = SnO₂

2. The balanced chemical reaction between NH₃ and O₂ is as follows;

4NH₃ + 5O₂ --> 4NO + 6H₂O

Thanks