Question

H In a similar experiment, tin was burned in air. Calculate the empirical formula for the oxide of tin using the following data: Mass of crucible, cover and tin sample = 21.76g Mass of empty crucible with cover = 19.66g Mass of crucible, cover and sample after heating = 22.29g

Answer 1

Mass of Sn = 21.76 g - 19.66 g

= 2.10 g

Mass of O = 22.29 g - 21.76 g

= 0.53 g

we have mass of each elements as:

Sn: 2.1 g

O: 0.53 g

Divide by molar mass to get number of moles of each:

Sn: 2.1/118.7 = 1.769*10^-2

O: 0.53/16.0 = 3.313*10^-2

Divide by smallest to get simplest whole number ratio:

Sn: 1.769*10^-2/1.769*10^-2 = 1

O: 3.313*10^-2/1.769*10^-2 = 2

So empirical formula is:SnO2

Answer: SnO2