Question

Copper(I) oxide will react with oxygen gas to produce copper(II) oxide. If 95.3 g of copper(I) oxide is reacted, how many grams of oxygen will be needed?

Answer 1

The balanced reaction between copper(I) oxide and oxygen can be written as follows.

Cu₂O + 1/2 O₂ 2CuO

The mole ratio of copper(I) oxide to oxygen = 1:1/2

Now, the no. of moles of copper(I) oxide = 95.3 g/(143.09 g/mol) = 0.666 mol

Now, the no. of moles of oxygen should be 0.666/2 mol = 0.333 mol

Therefore, the required mass of oxygen = 0.333 mol * 32 g/mol = 10.656 g