aluminium is present in period 3 and group 13 ,so atomic number is 13, so the valence electron is 3
electronic configuration is 1s22s22p63s23p1 so it will exhibit valency of +3 after the loss of 3 valence electron
oxygen is present in period 2 and group 16(group 6) ,so atomic number is 6, so the valence electron is 6
electronic configuration is 1s22s22p4 so it will exhibit valency of -2 after the gain of 2 in valence shell to attain stability
boron is present in same group of aluminium i.e. group 13(groupIII) ,so atomic number is 5, so the valence electron is 3
electronic configuration is 1s22s22p1 so it will exhibit valency of +3 after the loss of 3 valence electron to attain stability
therefore the chemical formula between boron and oxygen would be B2O3 [charges interchange their position]
ii) The balanced equation between chromium metal and sulphur is
2Cr +3S Cr2S3
thus we see 2 moles of chromium reacts with 3 moles of sulphur to produce 1 mole of chromium sulphide
1 mole of any substance = molecular mass of that substance
from literature molecular mass of chromium sulphide is 200 g
atomic mass of sulphur is 32 gm
moles of chromium sulphide =mass of product/molecular mass of chromium sulphide
moles of chromium sulphide=0.963g/200g = 4.815 *10-3 mole
1mole of chromium sulphide produced by 3 moles of S
4.815 *10-3 mole of chromium sulphide produced by 3 *4.815 *10-3moles of S
4.815 *10-3 mole of chromium sulphide produced by 0.0144 moles of S
1mole of S =32 g
0.0144 moles of sulphur = 0.0144 *32 g =0.4622 g of S
0.4622 g of S has reacted to produce 0.963 g of product
ii) theemperical formula of chromium sulphide is Cr2S3 because
sulphur is present in period 3 and group 16(group 6) ,so atomic number is 16, so the valence electron is 6
electronic configuration is 1s22s22p63s23p4so it will exhibit valency of -2 after the gain of 2 in valence shell to attain stability
chromium is present in period 4 , atomic number is 24,
electronic configuration is1s22s22p63s23p64s23d6 so it will exhibit valency of +3 after the loss of 3 in valence shell to attain stability as the d orbital will be half filled 1s22s22p63s23p63d5
Cr+3:S2- =Cr2S3 [charges interchange their position]
Using the given formula of aluminum oxide, Al2O3, refer to the periodic table and predict the empirical formula fo...
A 0.500-g sample of chromium metal reacted with sulfur powder to give 0.963 g of product. a) The mass of sulfur that reacted is _____ b) The empirical formula of the chromium sulfide is _____
DATE NAME SECTION POSTLABORATORY ASSIGNMENT 1. Predict the empirical formula for each of the following compounds given the formula of magnesium oxide, MgO. (a) calcium oxide (b) strontium oxide (c) barium oxide (d) radium oxide 2. Predict the empirical formula for each of the following compounds given the formula of sodium chloride, NaCl. (a) sodium fluoride (b) potassium chloride (c) lithium bromide (d) rubidium iodide 3. A 1.250 g sample of copper wire was heated in air and reacted with...
5. A 0.565-8 sample of cobalt metal reacted with excess sulfur powder to give 1.027 g of cobalt sulfide Calculate the empirical formula of the product. 6. A 0.750-g sample of tin foil was heated in air and reacted with oxygen gas to give 0.953 g of tin oxide. Calculate the empirical formula of the product. 7. (optional) A 1.000-g sample of red phosphorus powder was burned in air and reacted with oxygen gas to give 2.291 g of phosphorus oxide. Calculate...
5. A 1.000-g sample of iron metal reacted with sulfur powder to give 1.574 g of prod Calculate the empirical formula of the iron sulfide.6. A 1.000-g sample of iron metal reacted with sulfur powder to give 1.861 g of product Calculate the empirical formula of the iron sulfide.
1. Predict the empirical formula for each of the following compounds given the formula of magnesium oxide, Mgo. (a) calcium oxide (b) strontium oxide (c) barium oxide (d) radium oxide 2. Predict the empirical formula for each of the following compounds given the formula of sodium chloride, NaCl. (a) sodium fluoride (b) potassium chloride (d) rubidium iodide (c) lithium bromide 3. A 1.250-g sample of copper wire was heated in air and reacted with oxygen to give 1.565 g of...
40.505-8 sample of cobalt metal reacted with excess sulfur powder to give 1.027 g of cobalt sulfide. Calculate the empirical formula of the product. D. 565. Cox Imal Co A 0.750-g sample of tin foil was heated in air and reacted with oxygen gas to give 0.953 g of tin oxide. Calculate the empirical formula of the product.
1. A 0.750-g sample of tin metal reacts with 0.201 g of oxygen gas to form tin oxide. Calculate the empirical formula of the tin oxide. 2. A 0.565-g sample of cobalt metal reacts with excess sulfur to give 1.027 g of cobalt sulfide. Calculate the empirical formula of the product. 3. A 1.164-g sample of iron filings reacts with chlorine gas to give 3.384 g of iron chloride. Calculate the empirical formula of the product? 4. A 0.626-8 sample of copper oxide...
5-8 sample of cobalt metal reacted with excess salfiur powder to give 1.00 Calculate the empirical formula of the product olo. Imal Co 55-g sample of cobalt metal reacted with excess sulfur powder to give 1.027 - Calculate the empirical formula of the product.
7. A 0.250-g sample of calcium metal is heated in a 38.500-g crucible to form calcium oxide. The resulting crucible and product weigh 38.850 g. Refer to Example Exercise 1 and determine the empirical formula of calcium oxide. DATE DATA TABLE A Empirical Formula of Magnesium Oxide mass of crucible and cover + magnesium metal (before heating) mass of crucible and cover mass of magnesium metal mass of crucible and cover + magnesium oxide (after heating ) 0000 mass of...
A 1.000-g sample of cobalt metal reacted with sulfur powder to give 1.548 g of product. Record your numbers to 3 significant figures. Do not use exponential notation or subscripts in your answers. a) The mass of sulfur used in the reaction is b) The number of moles of cobalt is moles and the number of moles of sulfur is moles. c) Using their ratio of number of moles, the empirical formula of the cobalt sulfide is Draw the Lewis...