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In this equation, CrO42-(ag) + H2O(l) → CrO2 (ag) + OH-(ag), the change in oxidation number of the chromium atom is a. decrea

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croyacaq) + H2014) Croacaq) tou-laq) Oxidation state of a-8=-2 Chalin Croy2- ) a=t6. oxidation state of __2_-42- 1 cola) in cPlease upvote the answer

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