Question

What is the bond order for the polyatomic ion OF^-

Is this polyatomic ion paramagnetic or diamagnetic?

How many sigma bonds and pi bonds does this polyatomic ion have?

If you don't mind, I would love to see how you set up the diagram.

Answer 1

Answer: Hey dear student find the solution of your query, if you have any doubt feel free to ask. Thanks!! To calculate the bond order of the polyatomic ion OF- First we need to calculate the total number of electrons present in this polyatomic ion = 8 + 9 +1= 18 Than write the electronic configuration of polyatomic ion OF- = (ols) (0*1s) 2 (625) ?(0*2s) (62p.) 2 (nt 2px) 2 (n 2pv) (T* 2px) 2(1* 2pv) 2 With the help of above electronic configuration we select: Bonding electrons No = 10, Antibonding electrons N= 8 Bond order = (Bonding electrons No - Antibonding electrons N)/2 On putting the value: Bond order = (10 - 8)/2 = 1 The bond order of the polyatomic ion OF- = 1 Polyatomic ion OF- is diamagnetic in nature because in the filling of electrons all electrons are paired. The presence of one sigma bond and there is no pi bond present in the polyatomic ion OF = 1 Polyatomic ion OF = (ols) 2 (0*1s) 2 (625) ?(* 2s) (62pz) 2 (1 2px) 2 (n 2py) ?(n* 2px) 2 (n* 2py) 2