Question

What is the bond order for HF? Is the HF molecule predicted to be paramagnetic or diamagnetic? Use the M0 diagram to predict where the electron density in the HF bond lies, closer to the H atom or closer to the F atom? Explain. Now draw the Lewis structure for H F.

Answer 1

The electronic configuration of HF is, 2p, Bond order specifies the strength of the bond. Bond order is the number of bonds present in between the atoms. Bond order is calculated as B.O- (number of bonding electrons) - (number of antibonding electrons) ]- Thus, according to above MOT diagram, the bond order of HF is, B.O (2-0 в.о Thus, the bond order of HF is 1 From the electronic configuration of HF molecule, all the electrons are paired. Thus, the molecule HF is diamagnetic. The molecular orbital energy level diagram for homonuclear diatomic molecule HF ion is,

2p 1s 2P 2s 2s 1s 1s A.O of H M.O of HF A.O of F F is more electronegative than H-atom. Therefore, the atomic orbital of F-atom is lower irn energy than H-atom. Thus, the bonding electrons (electron density) are closer to the more electronegative F- atom. The electronic configuration of F is, F have 5 valence electrons. Calculate the total number of valence electrons in HF as follows HF=1+7 The Lewis structure of HF molecule is,