Glycerol, C3H8O3, is a substance used extensively in the manufacture of cosmetics, foodstuffs, antifreeze, and plastics. Glycerol is a water-soluble liquid with a density of 1.2656 g/mL at 15°C. Calculate the molarity of a solution of glycerol made by dissolving 80.000 mL glycerol at 15°C in enough water to make 350.00 mL of solution. M
mass of C3H8O3 = density * volume
= 1.2656 g/mL * 80.000 mL
= 101.248 g
Molar mass of C3H8O3,
MM = 3*MM(C) + 8*MM(H) + 3*MM(O)
= 3*12.01 + 8*1.008 + 3*16.0
= 92.094 g/mol
mass(C3H8O3)= 101.248 g
use:
number of mol of C3H8O3,
n = mass of C3H8O3/molar mass of C3H8O3
=(1.012*10^2 g)/(92.09 g/mol)
= 1.099 mol
volume , V = 3.5*10^2 mL
= 0.35 L
use:
Molarity,
M = number of mol / volume in L
= 1.099/0.35
= 3.141 M
Answer: 3.14 M
Glycerol, C3H8O3, is a substance used extensively in the manufacture of cosmetics, foodstuffs, antifreeze, and plastics....
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