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7. A small amount of CuSO4*5H20 (0.973 g) was dissolved in 100.0 mL of water, When...
A 3.7145-g portion of disodium EDTA dihydrate (M.W. 372.24) was dissolved in enough distilled water to...
A 3.7145-g portion of disodium EDTA dihydrate (M.W. 372.24) was dissolved in enough distilled water to prepare 1.000 liter of solution. A 100.0-mL water sample was adjusted to pH 10 and titrated to endpoint with 11.23 mL of the EDTA solution. Calculate the concentration of the EDTA solution and th e hardness of the water sample. Express the hardness of mg caCO3 /L.
A 4.36-g sample of an unknown alkali metal hydroxide is dissolved in 100.0 mL of water....
A 4.36-g sample of an unknown alkali metal hydroxide is dissolved in 100.0 mL of water. An acid-base indicator is added and the resulting solution is titrated with 2.50 M HCl(aq)solution. The indicator changes color signaling that the equivalence point has been reached after 17.0 mL of the hydrochloric acid solution has been added. Part B What is the identity of the alkali metal cation: Li+, Na+, K+, Rb+, or Cs+? Li+ Na+ K+ Rb+ Cs+ Part A What is...
A 4.36 g sample of an unknown alkali metal hydroxide is dissolved in 100.0 mL of...
A 4.36 g sample of an unknown alkali metal hydroxide is dissolved in 100.0 mL of water. An acid-base indicator is added, and the resulting solution is titrated with 2.50 M solution of HCl. The indicator changes colour, signalling that the equivalence point has been reached after 17.0 mL of the hydrochloric acid solution has been added. Determine the molality of this alkali metal hydroxide solution and What is the mass percentage of the metal hydroxide in the solution? Determine...
Answer units Save Question 7 (10 points) A 100.00 mL sample of hard water is to...
Answer units Save Question 7 (10 points) A 100.00 mL sample of hard water is to be titrated with 0.03505 M EDTA solution. A small amount of Mg2+ (that required 1.63 mL of EDTA to titrate as a blank solution) is added to the hard water sample. This sample requires 13.47 mL of EDTA to reach the endpoint. What volume of EDTA is used in titrating the Ca2+ in the hard water? Your Answer units Answer Save
A 0.6004 g sample of Ni/Cu condenser tubing was dissolved in acid and diluted to 100.0...
A 0.6004 g sample of Ni/Cu condenser tubing was dissolved in acid and diluted to 100.0 mL via a volumetric flask. Titration of both cations in a 25.00 mL aliquot of this solution required 45.81 mL of 0.05285 M EDTA. Mercaptoacetic acid and NH3 were then introduced; production of the Cu complex with the former resulted in the release of an equivalent amount of EDTA, which required a 22.85 mL titration with 0.07238 M Mg2+. Calculate the percentages of Cu...
A 0.4505 g sample of pewter, containing tin, lead, copper, and zinc, was dissolved in acid....
A 0.4505 g sample of pewter, containing tin, lead, copper, and zinc, was dissolved in acid. Tin was precipitated as SnO2⋅4H2Oand removed by filtration. The resulting filtrate and washings were diluted to a total volume of 250.0 mL. A 15.00 mL aliquot of this solution was buffered, and titration of the lead, copper, and zinc in solution required 35.10 mL of 0.001497 M EDTA. Thiosulfate was used to mask the copper in a second 20.00 mL aliquot. Titration of the...
A 4.75-g sample of an unknown compound is dissolved in enough water to make 100.0 mL...
A 4.75-g sample of an unknown compound is dissolved in enough water to make 100.0 mL of solution. This solution has an osmotic pressure of 25.0 torr at 25oC. Find the molar mass of the unknown.
A 0.3304-g sample of brass (containing lead, zinc, copper, and tin) was dissolved in nitric acid....
A 0.3304-g sample of brass (containing lead, zinc, copper, and tin) was dissolved in nitric acid. The sparingly soluble SnO2.4H2O was removed by filtration, and the combined filtrate and washings were then diluted to 500.0 mL. A 10.00-mL aliquot was suitably buffered; titration of the lead, zinc, and copper in this aliquot required 34.78 mL of 0.002700 M EDTA. The copper in a 25.00-mL aliquot was masked with thiosulfate; the lead and zinc were then titrated with 25.62 mL of...
A penny having a mass of 2.5340 g was dissolved in 20 mL of 8 M HNO3. The resulting solution was transferred to a 100.00-ml volumetric flask and diluted to the mark with water.
A penny having a mass of 2.5340 g was dissolved in 20 mL of 8 M HNO3. The resulting solution was transferred to a 100.00-ml volumetric flask and diluted to the mark with water. Then, a sample solution was prepared by transferring 10.00 mL of this solution to a 25.00- ml volumetric flask, adding 2.00 mL of 15 M NH3 and diluting to the mark with waterThe concentration of [Cu(NH3)4]2+ in the sample solution (determined using a Spectro Vis spectrophotometer)...
A titration was performed to standardize an EDTA solution. a) A 25.00 mL aliquot of a...
A titration was performed to standardize an EDTA solution. a) A 25.00 mL aliquot of a standard solution containing 0.01500 M Ca2+ required 42.87 mL of EDTA to reach the endpoint. The molarity of the EDTA solution is: ________ M b) That same EDTA solution was then used to titrate an unknown hard water sample. A 40.00 mL aliquot of unknown hard water required 34.21 mL of EDTA solution to reach a distinct endpoint. The concentration of Ca2+ ions (assuming...
Answer units Save Question 7 (10 points) A 100.00 mL sample of hard water is to be titrated with 0.03505 M EDTA solution. A small amount of Mg2+ (that required 1.63 mL of EDTA to titrate as a blank solution) is added to the hard water sample. This sample requires 13.47 mL of EDTA to reach the endpoint. What volume of EDTA is used in titrating the Ca2+ in the hard water? Your Answer units Answer Save
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