Answer units Save Question 7 (10 points) A 100.00 mL sample of hard water is to...

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Answer 1

Answer #1

mL of EDTA consumed by Ca²⁺ = mL of EDTA consumed by sample - mL of EDTA consumed by blank

= 13.47 mL - 1.63mL

= 11.84 mL

Since 1 L = 1000 mL, 11.84mL = 0.01184 L.

Moles of EDTA consumed by Ca²⁺ = molarity of EDTA x Volume of EDTA

= 0.03505M x0.01184 L

= 0.000414992 mol

Since EDTA and Ca²⁺ reacts 1:1 mole ratio,

the number of moles of Ca²⁺ in the hard water is 0.000414992 mol

Answer 2

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