Question

2.) How many grams of lithium bromide are dissolved in 125.0 grams of solution that is 5.00% sodium iodide by mass? 3.) How many milliliters of a 20.0% antibiotic solution must be administered to a patient who needs 1.75 grams of antibiotics? Assume the density of the solution is 1.18 g/mL.

Answer 1

- (2) 5.1 sodium iodide by massa sg in loog of solution so sg is sodium iodide. in 100 g of solution so liftiumbromide = (100g-sg) 1 = 95 geam 95 geam Litlium bromide is dissolved in loog of solution so, in 125 gram of solution, liftium bromide - is dissolved - as xlr geam 2 18 ким mass & Lithium bromide to be dissolved in 19 а.. , 2 - am ) . (3) 204. and boinic means = 20 geam of antibole in two geam of totection и хат 1 avi Sahе іn tоо зам 1 40 сол 50 (* Жан 1 avi Sове юju iѕ tо хат 4 доло,

muss f solution that contain 175 та m qhй Бокс Тоо Мон 1-к хат > 8-кам density a mass volume volume of antibonica Sohon mass of antisone soin density of solution - 2.415 ml 8.75 geam 1. tg a ml = 7.415 mi volume of antibonic Soul ow ю • діо 5w4