What is the % of Cu (MM = 63.55 g/mol) in Cu(CH3COO)2.H2O (MM = 199.65 g/mol)
% of an element in the compound = [mass of that element in the compoundx100 ]/ molar mass
So
% of Cu in given Cu(CH3COO)2.H2O = mass due to Cu x100/its molar mass
= 63.55g x100 /199.65 g
= 31.83%
What is the % of Cu (MM = 63.55 g/mol) in Cu(CH3COO)2.H2O (MM = 199.65 g/mol)
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