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If 2.27 g Ar are added to 3.66 atm He in a 2.00 L cylinder at 27.0 °C, what is the total pressure of the resulting! gaseous m
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Answer #1

M Atomic mass of Ar = 39.948 g/mol moles of Ar = Mass / At mass - 2.279/39.948 g/mol . = 0.05 6 & mol PV = nRT p. Phass me =

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