Hi. I'm having trouble solving the rate law for my chemistry lab report sheet. I'm unsure if I'm doing it right. Below is my trials
![Trial [1] [H202] Rate (M/s) 1 3.00 x 10^-2 M 1.50 x 10^-2 M. 5.05 x 10^-6 4.50 x 10^-2 M 1.50 x 10^-2 M 7.43 x 10^-6 4.50 x 1](http://img.homeworklib.com/questions/39304300-d6ec-11eb-a731-4be108eac7ce.png?x-oss-process=image/resize,w_560)
To calculate rate law, I choose experiment 1 and 2 for [I]x and experiment 2 and 3 for [H2O2]y. I got x=1 and y=1. This would make my rate law: rate = k [I-] [H2O2]
Is this correct? Please help! Thanks in advance
Homework Answers
![older with respect to [I] Divide trial I data by trial 2 data: 13:00x18ta I - 15.05X10% ats | (4.50x 16²m) - 1 7. 43X128 arts](http://img.homeworklib.com/questions/5cc64600-d6ec-11eb-867c-e19de39f974b.png?x-oss-process=image/resize,w_560)
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