Question

if 0.00594 moles N2O (g) effuses through an orifice in a certain period of time, how much NO2 (g) would effuse in the same time under the same conditions?

this is my work but Im not sure if I did it correctly. Could someone tell me if i did it correctly and show me a step by step of how

2. If 0.00594 mol N20 (9) effuses through an orifice (very small hole) in a certain period of time, how much NO2 (9) would effuse in the same time under the same conditions? M2 i rext 1 Mr > VNO2 - MN2O / 2 x t = JMs TN2o JM No2 gim MN2O = 28 gtmol 16 gimol = 449/mol N₂0 MNO2 = 1491 mol + 329/mol = 469/mol NO2 xlX NO2 - 449/mol N20 0.00594 mol N20 V 469/mol NO2 t X NO2 (0.00594 mol - = 0.978 mol (0.00594ool) 0.00594 mol N2O x = 0,00594 mol N20 x 0.978 mol x=0.0058094346 1 x 70.00581 mol NO2 |

they did it?

Answer 1

rale of effusion & I Molar mass e NO₂ = J MN2O INZO J MNO2 N NO2 2 v 44 - 0.00594 MNO₂= 0 978 0.00594 = 5.809 8103 moles effused - 0.00581 moles .? amount of No