Question

6. Draw the products of the following reactions ..O NBS, light NBS, light

Answer 1

Ans.

*Explanation*

1) when alkene react with NBS, light gives bromination at Alkylic position and reaction is by radical mechanism.

2) When alkane reacts with Br2 ,light gives Tertiary Bromination as a major product.Reaction is by radical mechanism

3) When alkane reacts with Cl2 ,light gives​​ mixture of chloro products. Reaction is by radical mechanism.

Please find attached file for all the answer of your questions.

Hope it will clear your concept.

as a NBS, Lights > Bo kihen N. Bromo succinimide react with Calkene) 'cyclopentene gives Cho) Bromination cet allylic position always. The reaction goes by Radical mechanism. Bo2, the- - Ohh light? + HBr + H & minor c4 By 99% (major) product at I and Broz in light react with alkane) 3-methyl pentane gives bromination at gº carbon is major product. Because free radicle stable at 8° c) H₂CY CH ca, light, 영셤 t 1 chloro 3 methyl pentane CH₃ T Ethy + CHE 2-chloro-3 meryl pentane CH2 tab 3 chlow 3 mettye pentane chlorine is react with alkane it will gives mixteere of products there will be chlorination at 1, 2 and 3 carbon, chlorination is not selective so will get mixture of product.