Question

solve the rest of the table & show work. thankyou

הייסו HCl(aq) Additions [H30+1 * [OH-] = Kw (0.1)(0-1). 17.08810-13 1.48X10 M 1.028x1014 100 2.13810-13 1.29810- 2M 1,049810-14 (6.1) (10-2) = 1.48810-2M Got2 Burette Reading 11.00mL T | Zooml 3.00ml 4,00ml 15.00ml 16.00 ml 17.00 mL 18.00ml 19,00mL TivoomL pH 12.15 12.09 12.04 11.96 11.89 11.79 11.68 11.44 11.18 703 Show a complete worked out set of calculations for the first addition,

Answer 1

- -19 -14 Buretle heading 1.00mL 2.00 mL 3.00 mL 4.00 mL 5.00 mL 6-00 mL 7.00 mL 8.00 mL 9.00 mL PH 12.15 12.04 12.04 11.96 11.89 11.79 11.68 11.44 -4 -) 3 -14 [130] [04] Kw 7.08 x 10' 1.48810 = 1.04x10 9.12X10" 10-96X102 .0-99x10 9:12X101 10-96X10 = 0.99810 10.9681013 9.12X103 = 0.998104 12.888103 7.76X10 = 0.998 10 4 16.21810S 6.16 8 10 = 0.99 x 10 20.89 X 10 4.78X10 = 0.99810T 36.3081013 2.95810 = 1.0781019 66.066 1013 1.51 x 10 = 0.99x1014 9.33x108 1071810 - 0.9991019 ty 4 1.18 10.00 mL 7.03 pH = -log [H30t Average kw = 10.03x109 10 [H3O+] = 10th bH & pot = 14 = 1.003x109 pon can be calculated using this equation pOH = -log[on [OH] = 10-pon -14 Average Kw = 1.003810