Which of the following is a monoprotic acid?
Group of answer choices
Na3PO4
H3PO4
H2PO4–
HPO42–
PO43–
Answer: HPO42- is a Monoprotic Acid
Expalanation: Monoprotic acid is a acid which can donate only one proton to an aqueous solution.
of the given group of choices-
1) Na3PO4 is a salt and does not belong to monoprotic acid as does not contains protons.
2) H3PO4 is a triprotic acid it can donate its 3 protons to an aqueous solution.
3) H2PO4- is a diprotic acid it can donate its 2 protons to an aqueous solution.
4) HPO42- is a monoprotic acid it can donate its 1 proton to an aqueous solution.
5) PO43– does not caontains protons
Which of the following is a monoprotic acid? Group of answer choices Na3PO4 H3PO4 H2PO4– HPO42–...
Which of the following equilibria represents the second ionization step of H3PO4? Group of answer choices HPO42-(aq) + H2O(aq) PO43-(aq) + H3O+(aq) H3PO4(aq) + 3H2O(l) PO43-(aq) + 3H3O+(aq) H2PO4-(aq) + H2O(l) HPO42-(aq) + H3O+(aq) H3PO4(aq) + 2H2O(l) HPO42-(aq) + 2H3O+(aq) H3PO4(aq) + H2O(l) H2PO4-(aq) + H3O+(aq)
Which of the following is a conjugate acid/ base pair? A) H3PO4, PO43- B) H2PO4 , PO43- C) HPO42-, PO43- D) H3PO4, HPO42-
Which equilibrium constant expression represents the first ionization of H3PO4 in water? A) [H+][H2PO4-]/[H3PO4] B) [H+][PO43-]/[HPO42-] C) [H+][PO42-]/[H2PO4-] D) [H+][H3PO43-]/[H3PO4] E) [H+][H3PO4]/[H3PO4]
Which of the following is not a conjugate acid-base pair? A H20 and H30+ B. H3PO4 and H2PO4 C. H3PO4 and HPO42- D. HPO42- and PO43 E. H2PO4 and HPO42-
What is the Bronsted Acid of H2PO4- + OH-àHPO42- + H2O? Group of answer choices H2PO4- OH- HPO42- H2O
18. Which of the following is the conjugate base of the dihydrogenphosphate ion, H2PO4-? A) H3PO4 B) NaH2PO4 C) OH- D) HPO42- E) PO43-
Question 38 (1 point) Which of the following is the conjugate acid of HPO42- H3PO4 H2P04 PO43- H30*
Which acid is the strongest? H3PO4 OH2PO4 HPO42- PO43- H2O
H3PO4 is a triprotic weak acid. What is the balanced equilibrium defined as Ka2 of H3PO4? O H2PO4 (aq) + H2O(l) =H2O*(aq) +HPO42- (aq) HPO42- (aq) + H2O(1) = OH(aq) + H2PO4 (aq) O HPO42-(aq) + H2O(1) =H20*(aq) + PO43-(aq) O H2PO4 (aq) + H2O(l) = OH" (aq) + H3PO4(aq) O H3PO.(aq) + H2O(1) =H30*(aq) + H2PO4 (aq)
2) Calculate the pH of 0.08 M Na2HPO4 H3PO4 S H+ + H2 PO4 pK1 = 2.1 H2PO4 5 H+ + HPO42- pK2 = 7.2 HPO42- 5 H+ PO43- pK3 = 12.3