Question

how do i calculate these?

1081 P1. Fill in the missing data in the reagent table below for the oxidation reaction starting with the provided number of grams of benzyl alcohol: Compound Amount Moles Equivalents MW (g/mol) Benzyl alcohol 0.100 g I 9 25x10-4 TEMPO (0.005 M) 2 mL 156.25 KBr 0.1 119.00 NaOCI solution (bleach) 2 mL 1.3% soln. (N/A) 0.4 N/A NaHCO, 0.5 84.01 Benzaldehyde 1166, 12u 0.01

Answer 1

Compound	Amount	Moles	Equivalents	MW(g/mol)
Benzyl Alcohol	0.100g	9.25 x 10-4	1	108.14
TEMPO(0.005M)	2mL	9.25 x 10-6	0.01	156.25
KBr	0.011g	9.25 x 10-5	0.1	119.00
NaOCl Soln (bleach)	2mL	1.3%soln.(N/A)	0.4	N/A
NaHCO3	0.039g	4.625 x 10-4	0.5	84.01
Benzaldehyde	0.098g	9.25 x 10-4	1	106.12

1 equivalents means the same number of moles. That is, do calculations according to the calculated moles of Benzyl alcohol. For 0.1 equivalents, 9.25 x 10-4 x 0.1 (= 9.25 x 10-5)moles likewise. Then, find the amount of compound (in gram) corresponding to the calculated moles using the equation, Moles x MW (g/mol).

In the case of TEMPO, we get the Moles as 9.25 x 10-6 by following the above method. If we arealculating the mole using the given amount and its molarity(M), we get the answer as 1 x 10-5. Both are approximately same. So, I am going with the former method.