Question

25. Predict the molecular shape and give the approximate bond angles of the PC, molecule A linear, 180" B trigonal planar, 120° C tetrahedral, 109.50 D trigonal pyramidal, 109.5° E. bent, 120 TAI 26. Which of the following molecules is polar? A. CCIA BHS C. SO D CO, E BeF: 27 Convert 689 torr to atm A. 0.689 atm B 0.760 atm C 0.906 atm DI 10 atm E 998 x 10' atm 28. If a 1.50 L gas sample is held at a constant temperature, and its pressure is changed from 2.30 atm to 3.60 atm, what will the final volume be? A 1.SOL B. 3.45 L C. 0.958 L D. 8.28 L E. 0.828 L 29 Given a fixed amount of gas held at constant pressure, calculate the volume it would occupy if a 2.00 L sample were cooled from 60.0°C to 30.0°C A. 1.00 L B 4.00 L C. 2.20 L D. 0.455 L E 1.82 L 30. A sample of gas initially occupies 3.35 L at a pressure of 0.950 atm at 13.0°C. What will the volume be if the temperature is changed to 22.5°C, and the pressure is changed to 1.05 atm? A 5.131 B. 3.13 L C. 1.79 L D 2.93 L E 3.58 L

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Answer 1

solution & (25) PUz valence é of Phosphorus no 513 - 4 Usp so geometry > Jetrahedral but shape 't uſe fo) 1 Ioigonal pyramidal. (109°5') 26 (A) CCl4 = mon-bolar LEATHS - Î (Polar) (6) Soz - (non-polar) (E) Ber F - Be-F 0-0-0 (Non-bolar - (Non-polar) (27) 1 atm= 760 toro =) Horra 1/760 atm - 689 torr =) 689 = 0.906 atm option (C) (28) at constt. temperature P, V,= P2 V2 final-volume -) 2.30X 1.50 = 3160 X V2 =) Vg = 0.958 F 1. It is Boyle's Law 29 at constt. Pressure w => 1273) . (301273) (D) Co r- 760 ess (60 V = from 1082 combined gas Law (30) PVL P2 Vz I 1 0.950 x 3.35 286 Na = 3.132 1.05 X V2 295.5