Question

Consider the following aldehydes and ketones. Which is the correct ranking in order of increasing reactivity...

Consider the following aldehydes and ketones. Which is the correct ranking in order of increasing reactivity towards nucleophilic addition to the carbonyl group?

A) 2-methylcyclohexanone < cyclohexanone < CH3CHO < H2CO

B) CH3CHO < 2-methylcyclohexanone < cyclohexanone < H2CO

C) cyclohexanone < 2-methylcyclohexanone < H2CO < CH3CHO

D) H2CO < cyclohexanone < CH3CHO < 2-methylcyclohexanone

E) cyclohexanone < 2-methylcyclohexanone < CH3CHO < H2CO

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Answer:-

Option A) 2-methylcyclohexanone < cyclohexanone < CH3CHO < H2CO is correct answer.

The reactivity of the carbonyl group depends upon the nature of groups attached to the carbonyl group. Any group that increases the positive charge over carbonyl carbon atom increases the reactivity of the carbonyl group.

Electron releasing group/groups (alkyl groups) when attached to the carbonyl carbon tend to neutralise the positive charge of carbonyl carbon and thereby decrease the reactivity of the carbonyl group.

Furthermore, greater the size of the alkyl substituents attached to the carbonyl carbon, the less is the reactivity of the carbonyl group because the larger groups around the carbonyl group hinder the attacking nucleophile from reaching the positively charged carbon (steric hindrance).

Add a comment
Know the answer?
Add Answer to:
Consider the following aldehydes and ketones. Which is the correct ranking in order of increasing reactivity...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT