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Two batteries supply current to the circuit figure
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Answer #1

Eeq = E1 + E2 ( batteries in series )

=> Eeq = 3+4.5 = 7.5 V

Veq = V1 + V2 + V3 ( resistances in series )

=> V3 = 7.5 - 2 - 3.5 = 2 V

=> current = V/R = 2/150 = 0.01333 Amp

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