You have a collection of six 2.1 kΩ resistors. What is the smallest resistance you can make by combining them? Express your answer with the appropriate units.
The smallest resistance can be obtained by connecting all these resistance in parallel.
Further,
For \(\mathrm{N}\) equal resistors in parallel, the reciprocal sum expression simplifies to:
\(\frac{1}{R_{\text {total }}}=\frac{1}{R} \times N\)
and therefore to:
\(R_{\text {total }}=\frac{R}{N}\)
So, Rsmallest \(=\left(2.1 \times 10^{\wedge} 3\right) / 6=350 \mathrm{Ohm}\)
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