A chemist prepares a solution of zinc nitrate (Zn(NO)) by measuring out 14.4 g of zinc...

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Answer 1

Answer #1

. given mass of Zn (NO3) = 14.4g. volume = 500ml = 0.5L Molecular mass of Zn(NO3)2 = 189.36g) mal Number of moles of Zn(NO3), 1

Answer 2

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