Question

A chemist working as a safety inspector finds an unmarked bottle in a lab cabinet. A note on the door of the cabinet says the cabinet is used to store bottles of tetrahydrofuran, ethanolamine, chloroform, pentane, and acetone. The chemist plans to try to identify the unknown liquid by measuring the density and comparing to known densities. First, from her collection of Material Safety Data Sheets (MSDS), the chemist finds the following information: liquid density tetrahydrofuran 0.893 cm ethanolamine chloroform pentane 0.63 cm acetone 0.79 Next, the chemist measures the volume of the unknown liquid as 0.909 L and the mass of the unknown liquid as 718. g. ne/com 00 Calculate the density of the liquid. Round your answer to 3 significant digits. Given the data above, is it possible to identify the liquid? ves no x 5 ? tetrahydrofuran ethanolamine chloroform pentane If it is possible to identify the liquid, do so.

Answer 1

The answer is attach below

ANTWER Chlonform Penfone | Acefone Ethanolamine Liquid ] Tetrahydrefnan yinen unknown valune at 0.9092 IL: 1000 cm So un knalen udung = gege 0.90 QX x 1000 cm3 9 Ich Cm Mass of anknown = 7189 Density = mass of unknown = 912g = 0.789878 9879 Mes volume of unknown Gogcm] Round to 3 significant chigit - Density of unlenecen = 790g ( 3 significand digit) → It is possible to identify the liguud Reason: I Acetine & unknown have same density hence - same compound . ) The possible. unt liquid in -) Acetines Reason: Acetine & unknown have some density = 0.750g.